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Sveta_85 [38]
3 years ago
10

Use the photo below:

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
4 0

Answer:

1. a. If ∠ 8 is supplementary to ∠ 9, then line x and line y are parallel lines whereas line s is the transverse line.

b. ∠ 7 = ∠ 4, gives line x and line y are parallel and line s is the transverse line.

c. ∠ 9 is supplementary to ∠ 12, then line s and line t are parallel and line y is the transverse line.

d. ∠ 9 = ∠ 11 {Alternate angles}

That means line s and line t are parallel and line y is the transverse line.

Step-by-step explanation:

1. a. If ∠ 8 is supplementary to ∠ 9, then line x and line y are parallel lines whereas line s is the transverse line.

b. ∠ 7 = ∠ 4.

Now, ∠ 7 = ∠ 2 and ∠ 4 = ∠ 9.

So, ∠ 2 = ∠ 9 {Alternate angles}

Hence, line x and line y are parallel and line s is the transverse line.

c. ∠ 9 is supplementary to ∠ 12, then line s and line t are parallel and line y is the transverse line.

d. ∠ 9 = ∠ 11 {Alternate angles}

That means line s and line t are parallel and line y is the transverse line.

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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

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3 years ago
Which equation matches the function described in the table?
BaLLatris [955]

Answer:

y = 4x - 1

Step-by-step explanation:

Equation y = 4x - 1 matches the function described in the table.

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Can anyone please solve this question
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The first number is 27 and the second number is 45 so the ratio would be 27;45
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-2x + 3x - 5 = 6 - 21<br><br> FIND x
trasher [3.6K]

Before we do any solving, we need to simplify both sides.

On the left, we can simplify -2x + 3x - 5 to x - 5.

On the right, we can simplify 6 - 21 to -16.

So we have x - 5 = -16.

Solving from here, we add 5 to both sides to get x = -11.

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