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4 years ago

How to calculate a pid controller

Computers and Technology

1 answer:

pishuonlain [190]4 years ago

5 0

Answer:

Control by PID1

is a control method often used for servos.

Don't you know what a bondage is? Well, it's a system, capable of reaching and

maintain a setpoint thanks to the measurements it performs.

Imagine, for example, in a car on the highway. You want to drive at 130Km / h

without having to press the accelerator. Your car's cruise control should

by itself maintain this speed. When approaching a slope the system "notices" that for

the same power at the level of the motor, it no longer reaches the 130 km / h setpoint and will add a

little acceleration. Yes but by how much? And how long will it take for the system to

stabilize around the setpoint?

That's the whole servo problem and PID control is one way to solve it!

PID is the most widely used regulator in industry. The idea of this control body is to

intentionally modify the value of the error which remains between the setpoint and the measurement

performed.

For example in the case of a position control the error would be: ε = c (p) - s (p)

In the case of proportional control, the error is virtually amplified by a certain gain

constant that should be determined according to the system.

Setpoint (t) = Kp.ε (t)

What in Laplace gives:

Setpoint (p) = Kp.ε (p)

Explanation:

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Consider a binary search tree where each tree node v has a field v.sum which stores the sum of all the keys in the subtree roote

AVprozaik [17]

Answer:

Each time you insert a new node, call the function to adjust the sum.

This method has to be called each time we insert new node to the tree since the sum at all the

parent nodes from the newly inserted node changes when we insert the node.

// toSumTree method will convert the tree into sum tree.

int toSumTree(struct node *node)

{

if(node == NULL)

return 0;

// Store the old value

int old_val = node->data;

// Recursively call for left and right subtrees and store the sum as new value of this node

node->data = toSumTree(node->left) + toSumTree(node->right);

// Return the sum of values of nodes in left and right subtrees and

// old_value of this node

return node->data + old_val;

}

This has the complexity of O(n).

Explanation:

6 0

3 years ago

. ____________is/are the JSP ImplicitObject(s).sessionapplicationconfigAll of GivenNone of Given

Lynna [10]

Answer:

All of Given

Explanation:

JSP provides a number of implicit objects which are made available by the container and can be used directly in scriptlets. These objects include:

session
application
config
out
request
response
pageContext
page
exception

Example usage:

<% session.setAttribute("userid","demoid"); %>

<% application.getContextPath(); %>

<% out.println(config.getServletName()); %>

5 0

4 years ago

What effect would excluding quotation marks from a search phrase have?

n200080 [17]

Answer: C

it would broaden the search

Explanation:

Placing quotation marks around a search term or phrase limits your search to that exact term or phrase. Without the quotes, your search engine may return all results that contain each separate word. Placing AND between your keywords will return results that only include both or all your keywords.

4 0

3 years ago

What is the decimal number of binary number 1101011 if the binaryis represented as a(n)

Kruka [31]

Answer:

a. Unsigned integer 107

b. Signed magnitude integer -43

c. One’s complement integer -20

d. Two’s complement integer 21

e. ASCII character k

Explanation:

a) For unsigned integer,

We put this value in representation of binary and put binary number in it.

we will place 1, 2, 4, 8, 16, 32, 64, 128 ...(powers of two)

64 32 16 8 4 2 1

1 1 0 1 0 1 1

The positions at 1 is present,we will add those numbers.In this (64+32+8+2+1) =107 is there.

So,107 will be the representation.

b)For signed magnitude integer,

The representation is just the same,but as signed integers the first bit represent the negative number.

64 32 16 8 4 2 1

1 1 0 1 0 1 1

The first bit is for Negative(-),then we will add other number where 1 is present.In this (32+8+2+1)=43.We will add (-) due to signed integers.

So,-43 will be the representation.

c) For One's complement integer,

We will compliment the bits of binary number.At the place of 1 ,place 0 and at the place of 0,place 1.

1 1 0 1 0 1 1

Compliment 0 0 1 0 1 0 0

Then,We put this value in representation of binary and put binary number in it, we will place 1, 2, 4, 8, 16, 32, 64, 128 ...(powers of two)

64 32 16 8 4 2 1

0 0 1 0 1 0 0

The positions at 1 is present,we will add those numbers.In this (16+8)=20 we will put negative at the starting because of the compliment

So, -20 will be the representation.

d)For Two's complement integer,

After compliment of bits At the place of 1 ,place 0 and at the place of 0,place 1.Then,we add 1 bit to the Least significant bit(Lsb).

1 1 0 1 0 1 1

Compliment 0 0 1 0 1 0 0

Add 1 to Lsb 0 0 1 0 1 0 0

+ 1

Number 0 0 1 0 1 0 1

Then,We put this value in representation of binary and put binary number in it, we will place 1, 2, 4, 8, 16, 32, 64, 128 ...(powers of two)

64 32 16 8 4 2 1

0 0 1 0 1 0 1

The positions at 1 is present,we will add those numbers.In this (16+8+1)=21

So,21 will be the representation.

e. For ASCII character,

First,convert it into decimal

We multiply bits with 2^n,from ascending numbers to 0 to (n-1),and add them

= 1 * 2^6 + 1*2^5 + 0* 2^4 + 1*2^3 + 0* 2^2 + 1*2^1 + 1* 2^0

= 64+32+8+2+1

= 107

Then,we check in Ascii table 107 decimal number's position ,k is there.

So,k will be the representation.

8 0

3 years ago

Select the correct answer.

SpyIntel [72]

Answer:

i think real time fluid dynamics

Explanation:

3 0

3 years ago