All categories

3 years ago

Which model is 85% Shaded

Mathematics

1 answer:

Margarita [4]3 years ago

7 0

Answer:

cant tell

Step-by-step explanation:

need more explanation

You might be interested in

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago

Please help me with all thank you

crimeas [40]

1. 7 : 07
2. 9 : 45
3. 6
4. 2 : 25
5. 8
6. 17

5 0

3 years ago

Simplify the given expression below: (7-3i)•(2-i)

Dimas [21]

when multiplying two binomials together we use the F.O.I.L. method:

First

Outer

Inner

Last

(7-3i)(2-i)

First: 7 * 2 ..... Outter: 7 * -i .... Inner: -3i * 2 ...... Last: -3i * -i

First: 14 ...... Outter= -7i ..... Inner: -6i .... Last: 3i^2

putting this together we get 14-7i-6i+2i^2

We combine like terms and end up with 2i^2-13i+14

5 0

3 years ago

Help find the area to this figure fasttt

Lynna [10]

Answer:

i can't see it was blur

i can't answer can you pic it again

3 0

3 years ago

Read 2 more answers

7.4 Practice

pickupchik [31]

The simulation of the medicine and the bowler hat are illustrations of probability

The probability that the medicine is effective on at least two is 0.767
The probability that the medicine is effective on none is 0
The probability that the bowler hits a headpin 4 out of 5 times is 0.3281

<h3>The probability that the medicine is effective on at least two</h3>

From the question,

Numbers 1 to 7 represents the medicine being effective
0, 8 and 9 represents the medicine not being effective

From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two

So, the probability is:

p = 23/30

p = 0.767

Hence, the probability that the medicine is effective on at least two is 0.767

<h3>The probability that the medicine is effective on none</h3>

From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none

So, the probability is:

p = 0/30

p = 0

Hence, the probability that the medicine is effective on none is 0

<h3>The probability a bowler hits a headpin</h3>

The probability of hitting a headpin is:

p = 90%

The probability a bowler hits a headpin 4 out of 5 times is:

P(x) = nCx * p^x * (1 - p)^(n - x)

So, we have:

P(4) = 5C4 * (90%)^4 * (1 - 90%)^1

P(4) = 0.3281

Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281