What is the elimination of 2a+3b=12 and 5a-b=13
2 answers:
2a plus 3b =12
5a minus 1b =13 multiply this by -3 to match 3b in equation 1
2a plus 3b =12
-15 plus 3b =-36
plus 15 plus 15
3b= -21
divide by 3 on both sides
b= -7
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so if x = -1, let's plug that in the second equation
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5+y = 5
y = 0
Always- their slopes are always opposite reciprocals of each other
Answer:
y = x + 5
Step-by-step explanation:
m = (0 --3 )/(-5--8)= 1
y - 0 = 1(x - - 5)
y = x + 5