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Snowcat [4.5K]
3 years ago
7

Following a dramatic drop of 500 points in the Dow Jones Industrial Average in September 1998, a poll conducted for the Associat

ed Press found that 92% of those polled said that a year from now their family financial situation will be as good as it is today or better. which of the following terms describes the number 92%? a. statistic. b. sample. c. sample parameter. d. population parameter. e. population.
Mathematics
1 answer:
fredd [130]3 years ago
7 0

Answer:  a. statistic

Step-by-step explanation:

  • Population : It is a set of all possible observations that can be made regarding a study by the researcher.
  • Sample : It is finite subset of population that represents the population in  the researcher's analysis.
  • Population parameter : It is a value that is calculated from the entire population such as population mean , population proportion etc.
  • Statistics : It is a value that is calculated from the sample taken out from population.

Since ,The group of people who took poll are representing the sample.

Therefore, 92% of those polled said that a year from now their family financial situation will be as good as it is today or better that means 92% describes a statistics.

Thus , the correct answer is a. statistic

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Let $f(x) = 12x^9 + x$. Find $f(3) + f(-3)$.
BlackZzzverrR [31]

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Ok, here goes:  f(3) means take f(x) and plug in 3 wherever we see x.  So

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Likewise, f(-3) means take f(x) and plug in (-3) wherever we see x.  So

f(-3) = 12*(-3)9 + (-3) = -236196 - 3

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5 friends need to split 4 candy bars how much does each friend get
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3 years ago
B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =
jolli1 [7]

I suppose you mean

g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)

Differentiate one term at a time.

Rewrite the first term as

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Then the product rule says

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'

Then with the power and chain rules,

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}

Simplify this a bit by factoring out \frac12 (36-x^2)^{-3/2} :

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}

For the second term, recall that

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