Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

Hence the bounds of the interval are:
As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
More can be learned about the z-distribution at brainly.com/question/25890103
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Can you show me the diagram
10. A 11. D 12. A (wasn’t too sure about question 12)
Answer:
the answer to the problem is -18
Answer:
D. 100
Step-by-step explanation:
1. Find the z-score: 165-176/11.4 = -1.2
2. Find the percentage of the z-score. Here it's 16.85%
3. Because we are searching for the amount of members that weigh MORE than 165 pounds and not LESS, we need to find the greater percentage by subtracting 16.85% from 100% which is 83.15%. This is the percentage of people that weigh more than 165 pounds.
4. Multiply the percentage by the number of members: 83.15%*120 = 99.78
5. Round it to a whole number because someone can't be 0.78 of a person. You get 100 members.
Also, I took the test :)