Answer:
False
Step-by-step explanation:
Given that a high school reports that its students' SAT scores were down by 12% in one year. The next year, however, the test scores rose by 20%.
Let score initially be 100
Down by 12
Next year score 88
For succeedingyear
increase is 20% =
Score in the 2nd year = 
Hence overall scores improvement is 5.6% and not 8%
The general formula for the margin of error would be:
z * √[p (1-p) ÷ n]
where:
z = values for selected confidence level
p = sample proportion
n = sample size
Since the confidence level is not given, we can only solve for the
<span>√[p (1-p) ÷ n] part.
</span>
p = 44/70
n = 70
√[44/70 (1 - (44/70) ÷ 70]
√[0.6286 (0.3714)] ÷ 70
√0.2335 ÷ 70
√0.0033357 = 0.05775 or 0.058 Choice B.
y = 3x - 1
x - y = -9
Subs y in second equation.
x - (3x - 1) = -9
x - 3x + 1 = -9
-2x = -9 - 1
-2x = -10
x = -10/-2
x = 5
Subs x
y = 3x - 1
y = 3.5 - 1
y = 15 - 1
y = 14
Answer:
Plug in the values for x
Step-by-step explanation:
plug in x values into the equation
for example, plug -2 into the equation. y= -2(-2). y=4
So on and so forth