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Hatshy [7]
3 years ago
12

In the diagram, the measure of angle 3 is 105°. Which angle must also measure 105°? Angle1 Angle4 Angle6 Angle8

Mathematics
1 answer:
Lunna [17]3 years ago
8 0

Answer:

<h2><1</h2>

option A is the right option.

Here,

<3=105°

<1=<3(being vertically opposite angles)

<1=105°

Explanation:

Please see the attached picture.

There,

<AOC and <BOD are formed by intersected line segments and they lie to the opposite side of common vertex.They are called vertically opposite angles.<AOD and <BOC are another pairs of vertically opposite angles. Vertically opposite angles are always equal.

Hope this helps..

Good luck on your assignment...

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Answer please i will give brainliest
il63 [147K]

Step-by-step explanation:

a.

simply add both equations

x + y = 2

-3x - y = 5

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-2x + 0 = 7

x = -7/2

x + y = 2

-7/2 + y = 2

y = 2 + 7/2 = 4/2 + 7/2 = 11/2

b.

1/2 x + 2y = -13

x - 4y = 8

first multiply the first equating by 2

x + 4y = -26

x - 4y = 8

--------------------

2x + 0 = -18

x = -18/2 = -9

x - 4y = 8

-9 - 4y = 8

-4y = 17

y = -17/4

7 0
3 years ago
Help with this question, please!
labwork [276]

Answer:

Y Intercept: 0, 2.5

X Intercept: 3.5, 0

Explanation:

An Intercept is where a line crosses an axis. A Y Intercept is for the Y axis and the X intercept is for the X axis.

Also when writing coordinates, the x coordinate comes before the y one.

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8 0
2 years ago
The equation for the circle is:
ivann1987 [24]
Use completion of sq method
x^2+y^2+14x+10y-7=0
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WILL GIVE BRAINLIEST&amp; 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
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Fatoring Trinomials<br> x^2+2x=-1
Musya8 [376]

Answer:

\Huge \boxed{x=-1}

Step-by-step explanation:

x^2+2x=-1

Adding 1 to both sides of the equation.

x^2+2x+1=-1+1

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Factoring the left side of the equation.

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(x+1)(x+1) = 0

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Taking the square root of both sides of the equation.

\sqrt{(x+1)^2} =\sqrt{0}

x+1=0

Subtracting 1 from both sides of the equation.

x+1-1=0-1

x=-1

8 0
3 years ago
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