Answer:
Step-by-step explanation:
We would use the t- distribution.
From the information given,
Mean, μ = 2950
Standard deviation, σ = 115
number of sample, n = 25
Degree of freedom, (df) = 25 - 1 = 24
Alpha level,α = (1 - confidence level)/2
α = (1 - 0.98)/2 = 0.01
We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01
The corresponding z score is 2.492
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
2950 ± 2.492 × 115/√25
= 2950 ± 2.492 × 23
= 2950 ± 57.316
The lower end of the confidence interval is 2950 - 57.316 =2892.68
The upper end of the confidence interval is 2950 + 57.316 = 3007.32
The solution is correct.
Answer:
1.) is B. and C.
2.) from 1/2 to 1/6
i'm soooooo sorry if this is wrong
Step-by-step explanation:
Hello :
tan²(θ) = 3.. equi : tan(θ) = √3 or tan(θ) = -√3
1 ) tan(θ) = √3
tan(θ) = tan(<span>π/3)
</span>θ = π/3 +kπ k in Z
2)tan(θ) = -√3
tan(θ) = tan(-π/3)
θ = -π/3 +kπ k in Z
Answer:
Your answer is C and D
Step-by-step explanation:
9514 1404 393
Answer:
2
Step-by-step explanation:
The curve's highest value is -1.
The curve's lowest value is -5.
For a symmetrical wave like this*, the amplitude is half the difference between the highest and lowest values:
1/2(-1 -(-5)) = 2
The amplitude is 2.
_____
* There is no general agreement as to how to compute the amplitude when the wave is asymmetrical. Some authors use the same formula. Some consider the amplitude to be the maximum deviation from average. Some define only a "peak-to-peak" amplitude in those cases. The meaning of "amplitude" in those cases depends on the context in which the question is asked.
