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3 years ago

Does anyone know this one! Thanks

Mathematics

2 answers:

serious [3.7K]3 years ago

7 0

Answer: 22.4 cm!

Step-by-step explanation:

If you have the measurements of one side of an equal sided octagon, then you multiply that number (which in this case is 2.8) by 8. Hope this helps!

Scrat [10]3 years ago

5 0

Answer:

22.4 cm

Step-by-step explanation:

2.8 cm x 8 sides = 22.4 cm

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1) Find the values of 'a' and 'b' for the given parallelogram *

nataly862011 [7]

Answer:

first option

Step-by-step explanation:

In a parallelogram consecutive angle are supplementary, sum to 180, so

2a + 122 = 180 ( subtract 122 from both sides )

2a = 58 ( divide both sides by 2 )

a = 29

---------------

In a parallelogram the opposite sides are congruent, then

b + 6 = 10 ( subtract 6 from both sides )

b = 4

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2 years ago

Find the slope of the line passing through the points (5,7) and (-4,2).

Andre45 [30]

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6 0

3 years ago

Read 2 more answers

Alex, Bruno, and Charles each add the lengths of two sides of the same triangle correctly. They get 27 cm, 35 cm, 32 cm, respect

Vera_Pavlovna [14]

Answer:

47 cm.

Step-by-step explanation:

Alex, Bruno, and Charles each add the lengths of two sides of the same triangle correctly.

They get 27 cm, 35 cm, and 32 cm, respectively. Find the perimeter of the triangle, in cm

find:

Find the perimeter of the triangle, in cm. What is the most efficient strategy you can find to solve this problem?

<u>solution:</u>

27, 35, and 32 are each the sum of a different pair of sides of the triangle

Then 27 + 35 + 32 is the sum of all three sides, each counted twice.

Thus, 27 + 35 + 32 = 94 is twice the perimeter

therefore,

the perimeter of the triangle is 94/2 = 47 cm.

6 0

3 years ago

Read 2 more answers

The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i

Anit [1.1K]

Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

$a_n = ar^{n-1}$

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

the first term can be calculated as:

$16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128$

Thus, the required geometric sequence is

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

4 0

3 years ago

I just don’t understand how to do this?i need answers please

Maslowich

1.) 17.1g > 1.71mg
2.) 6.3cm< 63m
3.)1250ml>12.5
4.) 7/12 < 2/3
5.) 7/10 < 11/15

6 0

2 years ago