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erica [24]
3 years ago
13

Find the value of the variable and the measure of each labeled angle.

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer:

x+10

Step-by-step explanation:

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A parabola has a vertex at (4, 0) and passes through the point (6, 1). Which of the following is the equation of this parabola i
Doss [256]
Easy

y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a

thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
7 0
3 years ago
In a group discussion, which option is most clearly a clarifying question?
Mariulka [41]

Answer:

your answer should be d

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
in 1930 the average cost for a gallon of gasoline was $0.25. in 2007 the average cost for a gallon of gasoline is $2.60 what is
AlekseyPX
Hello! The first thing to do is to find the amount of change by subtracting both numbers. 2.60 - 0.25 is 2.35. Now, we set up a proportion by doing change/original = x/100. With the values plugged in, it would be written like this: 2.35/0.25 = x/100. Cross multiply the values in the proportion. When you do, you get 235 = 0.25x. Now, divide each side by 0.25 to isolate the "x". When you do that, x = 940. The price of gas has gone up 940% since 1930.
7 0
2 years ago
Read 2 more answers
Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1
kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant b^2-4ac applies to quadratic equations when they are organised in standard form: ax^2+bx+c=0.

All quadratic equations can be solved with the quadratic formula: x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}.

When b^2-4ac is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

<u />3x^2+5x=-1<u />

We're given the above equation. It hasn't been organised completely in ax^2+bx+c=0, but we can change that by adding 1 to both sides to make the right side equal to 0:

3x^2+5x+1=0<u />

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0
3 years ago
Round your answer to the nearest hundredth.<br> C<br> 5<br> B.<br> 7<br> ?<br> A
astraxan [27]

Answer:

If C is 5 and B is 7 the a is 9

7 0
3 years ago
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