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Y_Kistochka [10]
3 years ago
10

Given the following perfect square trinomial, fill in the missing term. x2 − 16x + ____

Mathematics
1 answer:
ahrayia [7]3 years ago
4 0

Answer:

x^{2}-16x+64

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You have the following perfect square trinomial given in the problem:

x^{2}-16+

2. To fill the missing term, you must divide the coefficient -16 by 2 and then you must square it, as following:

(\frac{-16}{2})^{2}=(-8)^{2}=64

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Find a mathematical model that represents the statement. F varies directly with s and inversely as the square root of d. f=6 whe
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Please help! posted picture of question
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Read 2 more answers
Find sin(a+B)
diamong [38]

Answer:

Cos A=5/13

we have

Cos² A=1-Sin ²A

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A=\sqrt{144/169}=12/13

again

Tan B=4/3

P/b=4/3

p=4

b=3

h=\sqrt{3²+4²}=5

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>

<u>n</u><u>o</u><u>w</u><u> </u>

<u>substitute</u><u> </u><u>value</u>

<u>Sin(A+B):</u>12/13*3/5+5/13*(-4/5)=36/65-4/13

<u>=</u><u>1</u><u>6</u><u>/</u><u>6</u><u>5</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>

6 0
2 years ago
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