How many moles of a gas sample are in a 10.0 L container at 298 K and 203 kPa? (Use the ideal gas law PV = nRT with R = 8.31 L-k
Pa/mol-K).
1 answer:
Ideal gas law: PV = nRT
P-pressure
V-volume
n-number of moles(m/M)
R-constant
T- temperature
State given info:
V=10L
T=298k
P=203kPa
R=8.31(only for kPa, for pressure at atm use 0.08206)
Sub in:
(203kPa)(10L)=n(8.31)(298)
Rearrange:
n= (203)(10) / (8.31)(298)
n = 0.819745mol in gas sample
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