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Fynjy0 [20]
2 years ago
12

What other inventions came because of the microscope? (These are inventions that are related to the microscope in some way.)

Chemistry
1 answer:
inn [45]2 years ago
3 0

Answer:

Explanation:Leeuwenhoek observed animal and plant tissue, human sperm and blood cells, minerals, fossils, and many other things that had never been seen before on a microscopic scale. He presented his findings to the Royal Society in London, where Robert Hooke was also making remarkable discoveries with a microscope.

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The kinetic energy of an object increases​
Tom [10]

Answer:

the kinetic energy of an object increases as the gravitational potential energy increases

Explanation:

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5 0
4 years ago
It takes Serina 0.25 hours to drive to school. Her route is 16 meters long. What is
Yakvenalex [24]

Answer:

60 (1 hour) × 0.25 = 15 minutes

15 ÷ 16 = 0.9375 meters per minute

5 0
3 years ago
The number of electrons present in 4.2 gram of methane is​
jeka94

Answer:

Explanation:

One CH4 molecules = 10 electrons ( Carbon 6e + 4Hydrogen 4e)

A mole of any substance witll have = 6.023*10^23 atom/ molecuels,

One mole of any substnce is equal is nothing but its moalr mass

Molar mass of CH4 = 16.04

It mean,

16.04  g of CH4 has = 6.023*10^23 molecules of methane

but

4.2 gram of CH4   = 6.023*10^23 * 4.2 /16.04 = 1.58*10^23 molecuels of CH4

So one molecule has =10 electrons

1.58*10^23 molecuels will have = 1.58*10^23  * 10 = 1.58*10^24

Hope this help you

3 0
3 years ago
Convert 7.6 × 105 cal to kiloJoules
Arisa [49]
Answer: 3.338832 kilojoules
4 0
2 years ago
Which of the following answers below is the correctly balanced half-reaction for the reduction of the SO4 ^-2 ion in acid soluti
Rom4ik [11]

Answer:

C

Explanation:

The oxidation number of Sulphur in SO4^2- is;

x + 4(-2) = -2

x - 8 = -2

x = -2 + 8

x = 6

Now,

the oxidation number of sulphur in H2SO3 is

2 (1) + x + 3(-2) = 0

2 + x -6 = 0

-4 + x = 0

x = 4

Hence, the oxidation number of sulphur changed from +6 to +4 which signifies  gain of two electrons as shown in option C.

8 0
3 years ago
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