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Maru [420]
3 years ago
10

A rectangle with sides 4 in. and 7 in. was enlarged in the ratio 1:2

Mathematics
1 answer:
Licemer1 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

The volume of a rectangular box is given to be 2

3 − 2

2 − 44 + 80.

If the length of the box is given to be x+5, what are the dimensions

of the rectangular base of the milk box? Show the complete

solution.

A. (2 − 3)( − 3)

B. (2 − 8)( − 2)

C. (2 + 8)( + 2)

D. ( − 8)( − 2)

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Lunna [17]

Answer:

8 green tshirts

Step-by-step explanation:

8 0
2 years ago
My friend needed help with this and I found the height through the theorem but can't figure out how to get the base of the overa
Aleksandr-060686 [28]

You found CD from the Pythagorean theorem to be ...

... CD = √(5² -2²) = √21

Since triangle ADC ~ triangle ACB, the ratios of corresponding sides are the same:

... AC/AD = AB/AC

... AB = AC²/AD

... AB = 5²/2 = 12.5 . . . . . . . the base of the overall triangle

_____

Then the area (A) is ...

... A = (1/2)bh

... A = (1/2)(12.5)(√21) ≈ 28.64 square units

_____

As you see here, the altitude of a right triangle divides it into three similar triangles. From smallest to largest, they are ...

... ADC ~ CDB ~ ACB

You can figure this using AAA similarity, since the smallest and largest triangles listed above share an acute angle vertex (∠A). That, together with the right angle, means all angles are congruent. After that, then you know ∠ACD ≅ ∠CBD, so you can show the middle sized triangle is similar to the other two.

6 0
2 years ago
Is 5/8 closer to 0,1/2, or 1
Rina8888 [55]


0= 0/8

1/2= 4/8

1= 8/8

5/8 is closer to 1/2.

4 0
2 years ago
Help me plsssssssssssssssss
asambeis [7]

Answer:

I would say 1.5in

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP!! Find the missing side and round answer to the nearest tenth.
Mariulka [41]
I got 18. i did this by using the SOH CAH TOA method. In this case you have the the angle and the hypotenuse, and you’re looking for the adjacent side, therefore you need to use CAH
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2 years ago
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