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Maru [420]
3 years ago
10

A rectangle with sides 4 in. and 7 in. was enlarged in the ratio 1:2

Mathematics
1 answer:
Licemer1 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

The volume of a rectangular box is given to be 2

3 − 2

2 − 44 + 80.

If the length of the box is given to be x+5, what are the dimensions

of the rectangular base of the milk box? Show the complete

solution.

A. (2 − 3)( − 3)

B. (2 − 8)( − 2)

C. (2 + 8)( + 2)

D. ( − 8)( − 2)

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How do i solve this problem?
Dominik [7]

Answer:

Step-by-step explanation:

surface area of one  can 2πrh+2πr²

=2πr(h+r)

≈2×3.14×3/2(4.25+1.5)

≈9.42(5.75)

≈54.165 in²

number of cans=1000/54.165

=18 cans

material used=18×54.165≈975 in²

material left=1000-975=25 in²

3 0
2 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n)=-6+(n-1)(1/5) A)-6,-5 1/5,
scoundrel [369]

Step-by-step explanation:

An arithmetic sequence is given by relation as follows :

A(n)=-6+(n-1)\dfrac{1}{5}

For the first term, put n = 1. So,

A(1)=-6+(1-1)\dfrac{1}{5}\\\\A(1)=-6

For fourth term, put n = 4. So,

A(4)=-6+(4-1)\dfrac{1}{5}\\\\A(4)=\dfrac{-27}{5}\\\\A(4)=-5\dfrac{2}{5}

For tenth term, put n = 10. So,

A(10)=-6+(10-1)\dfrac{1}{5}\\\\A(10)=-6+\dfrac{9}{5}\\\\A(10)=\dfrac{-21}{5}\\\\A(10)=-4\dfrac{1}{5}

Hence, the correct option is (C).

7 0
3 years ago
Three times a number increased by 7 is 100. Find the number.
velikii [3]

Answer:

31

Step-by-step explanation:

100-7= 93

93÷3=31

7 0
2 years ago
Read 2 more answers
How much fabric is needed to make a tent in the shape of a triangular prism with the following measures?
marshall27 [118]

Answer:

C) 273 ft²

Step-by-step explanation:

7x11x3=231

2x1/2x7x6=42

231+42=273

3 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
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