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riadik2000 [5.3K]
3 years ago
5

The sum of two numbers is 28. The first number, x, is three times the second number, y.

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

x=21

y= 7

Step-by-step explanation:

x+y = 28

x = 3y

Substitute the second equation into the first

3y+y = 28

4y = 28

Divide by 4

4y/4 = 28/4

y = 7

Now we need to find x

x = 3*y

x = 3*7

x = 21

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Answer:

63.4

Step-by-step explanation:

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5 0
3 years ago
I dont get how to solve this?
Alex

Answer:

Step-by-step explanation:

In standard form this could be rewritten as | b - 0 | > 6, which in words, says,

"b is greater than 6 units away from 0 on a number line".  If b is greater than 6 units away, both positive 6 and negative 6 are 6 units away from 0.  Because the values we need are greater than 6 units away from 0, we are starting at both 6 and -6 and moving away from 0.  

The "greater than" symbol indicates that this is a disjunction so the word "or" is used as opposed to in a conjunction where the word "and" is used.

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4 years ago
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Crazy boy [7]
A is the correct answer
6 0
3 years ago
If f(1)=6f(1)=6 and f(n)=nf(n-1)-4f(n)=nf(n−1)−4 then find the value of f(3)f(3).
alekssr [168]

Answer:

49

Step-by-step explanation:

6 0
3 years ago
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Solve the inequality.<br> 5q + 22-13
kirill115 [55]

Answer:

The answer is 5q + 9.

Step-by-step explanation:

1) Collect like terms.

5q + (22 - 13)

2) Simplify.

5q + 9

<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>5q</u><u> </u><u>+</u><u> </u><u>9</u><u>.</u>

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