Given :
A vector v = 10i - 24k.
To Find :
A vector of magnitude 3 in the direction of v = 10i - 24k.
Solution :
Unit vector in the direction of vector v is :

Now , vector of magnitude 3 in direction v is :

Hence , this is the required solution .
The answer is 14.27 :) correct me if wrong I think I am
Answer:
−135z
2
−2z
The 2 is representing Square
Step-by-step explanation:
(3z)
2
−4z+11−(12z)
2
+2z−11
Expand (3z)
2
.
3
2
z
2
−4z+11−(12z)
2
+2z−11
Calculate 3 to the power of 2 and get 9.
9z
2
−4z+11−(12z)
2
+2z−11
Expand (12z)
2
.
9z
2
−4z+11−12
2
z
2
+2z−11
Calculate 12 to the power of 2 and get 144.
9z
2
−4z+11−144z
2
+2z−11
Combine 9z
2
and −144z
2
to get −135z
2
.
−135z
2
−4z+11+2z−11
Combine −4z and 2z to get −2z.
−135z
2
−2z+11−11
Subtract 11 from 11 to get 0.
−135z
2
−2z
Step-by-step explanation:


Answer: The answer to your question would be
.