Question

Solve the system of equations y=x^2+3x-4 and y=2x-4

Answer 1

Answer:

A

Step-by-step explanation:

Given the 2 equations

y = x² + 3x - 4 → (1)

y = 2x - 4 → (2)

Substitute y = x² + 3x - 4 into (2)

x² + 3x - 4 = 2x - 4 ( subtract 2x - 4 from both sides )

x² + x = 0 ← in standard form

x(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x = 0

x + 1 = 0 ⇒ x = - 1

Substitute these values into (2) for corresponding values of y

x = 0 → y = 2(0) - 4 = 0 - 4 = - 4 ⇒ (0, - 4 )

x = - 1 → y = 2(- 1) - 4 = - 2 - 4 = - 6 ⇒ (- 1, - 6 )