Answer:
Step-by-step explanation:
Answer choice B is the correct answer the rest don't make sense.
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
Answer:
9
Step-by-step explanation:
Using the property that
a
m
a
n
=
a
m
−
n
, we have
3
4
2
2
=
3
4
−
2
=
3
2
=
9
Note that if we evaluated the numerator and denominator first, we would arrive at the same result:
3
4
3
2
=
81
9
=
9
Answer:
i think its 105
Step-by-step explanation:
