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Nady [450]
3 years ago
6

There are two triangles one has a base of 8 cm and a hieght of 10 cm the other has a base of 5 cm and a height of 13 cm which tr

iangle has a larger area
Mathematics
1 answer:
kramer3 years ago
7 0

Answer:

The triangle with base 8 cm and height 10 cm.

Step-by-step explanation:

A

r

e

a

△

=

1

2

⋅

b

a

s

e

⋅

h

e

i

g

h

t

△

1

a

r

e

a

=

1

2

⋅

8

⋅

10

=

40

△

2

a

r

e

a

=

1

2

⋅

5

⋅

13

=

32.5

 

40

>

32.5

∴

Area of first triangle is larger.

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Express 3km 2m as a decimal of 1km.
puteri [66]

Answer:

3.002 km

Step-by-step explanation:

1000 m = 1 km

1 m = 0.001 km

3 km + 2 m = 3 km + 2(0.001 km)

3 km + 2(0.001 km) = 3.002 km

6 0
3 years ago
Given: BDis a diameter<br> m 1 = 100°<br> m BC= 30°<br><br> m2 =<br><br> 30<br> 80<br> 100
skad [1K]

Answer:

∠2 = 80°

Step-by-step explanation:

Since BD is a diameter then

∠1 + ∠2 = 180°, that is

100° + ∠2 = 180° ( subtract 100° from both sides )

∠2 = 180° - 100° = 80°

4 0
3 years ago
Read 2 more answers
Brainliest* and show work and the answer to number 15
barxatty [35]

Step-by-step explanation:

perimeter of semicircle=πr+2r

\frac{22}{7}  \times 1 + 2 \:  \:  \:  \:  \:  \:  \: (d = 2r)  \:  \\  \\ 5.14ft \:  \:  \:  \:  \:  \:  \:  \:

4 0
2 years ago
How much smaller is the sum of the first 1000 natural numbers than the sum of the first 1001 natural numbers?
aleksandr82 [10.1K]

ANSWER

1001

EXPLANATION

The sum of the first n - natural numbers is

S_n=  \frac{n}{2} (2a + d(n - 1))

The sum of the first 1000 terms is

S_{1000}=  \frac{1000}{2} (2(1) + 1(1000 - 1))

S_{1000}=500 (1001)

S_{1000}=500500

The sum of the first 1001 terms is

S_{1001}=  \frac{1001}{2} (2(1) + 1(1001 - 1))

S_{1001}= 1001 \times (501)

= 501501

The difference is

501501 - 500500= 1001

5 0
2 years ago
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How to solve this problem by classifying systems of equations<br> 3x+4y=36<br> -5x=35-3y
marissa [1.9K]

Answer:

x=-32/29

y=9\frac {24}{29}

Step-by-step explanation:

3x+4y=36 Equation 1

-5x+3y=35 Equation 2

Multiplying equation 1 with 3 (value before y in equation 2) and equation 2 with 4 (value before y in equation 1) we obtain equations 3 and 4 as follows

9x+12=108 equation 3

-20x+12y=140 equation 4

Subtracting equation 3 from equation 4 we obtain

-29x=32

x=-32/29

To find the value of y, we substitute the value of x into equation 2 as initially given in the equation

-5(-32/29)=35-3y

-5(-32/29)-35=-3y

y=9\frac {24}{29}

7 0
3 years ago
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