Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
Step-by-step explanation:
By Pythagoras' Theorem, 6^2 + 8^2 = x^2.
x^2 = 36 + 64 = 100, x = 10.
We can solve this by setting up 2 equations. We can use any letters like. For now, I'll use x and y.
So now we know that x - y = 0.7 and x + y = 1.
Now we can eliminate one of the letters by adding or subtracting one equation from the other. I am going to eliminate y by adding the two together (the y and the -y cancel).
This gives us 2x = 1.7, and so x = 1.7 ÷ 2 = 0.85
Finally, we can substitute x for 0.85 back into one of the original equations to figure out what y equals. I'm going to use x + y = 1.
So now we have 0.85 + y = 1, so y = 1 - 0.85 = 0.15
The numbers, therefore, are 0.85 and 0.15 (you can check by using the other equation).
Hope this helps!
