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UkoKoshka [18]
3 years ago
10

Which of the following describes the zeros of the graph...​

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

d) 0 with multiplicity 3 , -3 with multiplicity 1 and - 6 with multiplicity 1

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<em>Given  polynomial equation  </em>

<em>                    ⇒        - x⁵ + 9 x⁴ - 18 x³ </em>

                    ⇒     - x³ ( x² - 9 x + 18 )

                    ⇒    - x³ ( x² - 6 x  - 3 x + 18)

                    ⇒    - x³ ( x(x -  6)  - 3( x - 6))

                   ⇒     - (x-0)³ (x-6)(x-3)

<em>∴ The Zeros of the given function is 0 with multiplicity 3 , -3 with multiplicity 1 and - 6 with multiplicity 1 </em>

<em></em>

                       

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see graph below

Explanation:

Given:

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\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

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Plotting the coordinates:

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