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Arturiano [62]
3 years ago
15

Round 3.047 to the nearest hundredth.

Mathematics
1 answer:
Phoenix [80]3 years ago
6 0
3.05 because it is tenth then hundredth after the decimal.
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Use graphing to find the solutions to the system of equations.
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In order to utilize the graph, first you have to distinguish which graph accurately pertains to the two functions.

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a store has 300 televisions on order, and 80% are high definition. how many televisions on order are HD?
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A rope is swinging in such a way that the length of the arc traced by a knot at its bottom end is decreasing geometrically. If t
nikdorinn [45]

Answer:

<em>The length of the arc on the sixth swing was </em><em>12.18 ft.</em>

Step-by-step explanation:

A rope is swinging in such a way that the length of the arc traced by a knot at its bottom end is decreasing geometrically.

The third arc is 22 ft. long and the seventh arc is 10 ft.

Hence, the 3rd term is 22 and 7th term is 10.

The length of the arc on the sixth swing is asked, so we have to calculate the 6th term.

We know the nth term in GP is,

T_n=ar^{n-1}

So,

T_3=ar^{3-1}=ar^2  ----------------1

T_7=ar^{7-1}=ar^6  ----------------2

Dividing equation 2 by 1,

\Rightarrow \dfrac{T_7}{T_3}=\dfrac{ar^6}{ar^2}

\Rightarrow \dfrac{10}{22}=\dfrac{ar^6}{ar^2}

\Rightarrow \dfrac{10}{22}=\dfrac{r^6}{r^2}

\Rightarrow \dfrac{r^6}{r^2}=\dfrac{10}{22}

\Rightarrow r^4=\dfrac{10}{22}

\Rightarrow r=\sqrt[4]{\dfrac{10}{22}}

\Rightarrow r=0.8211

Then the 6th term will be,

T_6=ar^{6-1}=ar^5  ----------------3

Dividing equation 2 by 3,

\Rightarrow \dfrac{T_7}{T_6}=\dfrac{ar^6}{ar^5}

\Rightarrow \dfrac{10}{T_6}=\dfrac{a(0.8211)^6}{a(0.8211)^5}

\Rightarrow \dfrac{10}{T_6}=0.8211

\Rightarrow T_6=\dfrac{10}{0.8211}=12.18\ ft

Therefore, the length of the arc on the sixth swing was 12.18 ft.


6 0
3 years ago
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