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Allisa [31]
3 years ago
10

Please try to answer,thank you!

Mathematics
1 answer:
belka [17]3 years ago
7 0

Given details show the how many hours of sleep the students take and and how much marks the students score in an examination.

Number of hours slept is taken in x-axis (abscissa).

Test score is taken in y-axis (ordinate).

Therefore, (x, y) = (hours slept, test score)

So, the ordered pairs set up to plot the scatter plot in the order (hours slept, test score).

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jake is hiking a trail that leads to the top of a canyon. The trail 4.2 miles long, and jake plans to stop for lunch after he co
Ksivusya [100]
The answer will be 2.2 miles

5 0
3 years ago
Calculate simple interest :
Elodia [21]

Answer:

the simple interest in both cases is 200 and 756 respectively

Step-by-step explanation:

The computation of the simple interest is shown below:

As we know that

Simple interest = P × r% × t

So

a. Simple interest is

= 2,500 × 8% × 1

= 200

b. The simple interest is

= 4,200 × 6% × 3

= 756

Hence, the simple interest in both cases is 200 and 756 respectively

5 0
3 years ago
Factor completely 64x2 − 49. (1 point)
Roman55 [17]

Answer:

(8x-7)(8x+7)

Step-by-step explanation:

This is a difference of squares polynomial of the form a^2-b^2=(a+b)(a-b). Since 64 and 9 are both perfect squares then take the square root of each so a=8 and b=7.

Factors:(8x-7)(8x+7)

6 0
3 years ago
What is the solution R-7=1?? Thank
cluponka [151]

Answer: R=8

Step-by-step explanation: R-7=1, R+7=1+7, R=8.

6 0
3 years ago
Read 2 more answers
What is the area of Shaded part?
svetlana [45]

Answer:

1π

Step-by-step explanation:

suppose the radius of semicircle P is r,

then the radius of semicircle Q = (r+d)/2  ... d≤r

radius of semicircle R = (r-d)/2

area P = 1/2 (r)²π

area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π

area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π

shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π

                                   = ((r² - d²)/4) * π

because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0

therefore the shaded area = ((2² -0²)/4)*π = 1π

8 0
2 years ago
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