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seropon [69]
4 years ago
14

What is the purpose of a punnett square?

Mathematics
2 answers:
ololo11 [35]4 years ago
8 0
This should be in the biology section. A Punnett square is a table to show all the possible outcomes of two parents mating. Specifically it deals with the genotypes and genetic combinations going from known parents to unknown potential offspring. 
Alja [10]4 years ago
4 0

Answer:

Explanation:

The Punnett square is a diagrammatic representation which involves a square that is used to predict the genotype of the offsprings after the cross breeding process. It was named by the Reginald Punnett. This diagram is drawn by the biologists so as to know the probability of occurrence of a particular genotype in the offsprings.

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The accountant charged $35 for the first hour of work and $23 for each hour after that.He earned a total of$127 how many hours d
dexar [7]

Answer:

He worked a total of 5 hours.

Step-by-step explanation:

The first hour the man makes $35 dollars for the first hour then for the other hours he earns $23 dollars, right? So we start off with 35.

35 = one hour.

35 + 23 = 2 hours .  =  58.

35  + 23 + 23 = 3 hours. =  81.

35 + 23 + 23 + 23 = 4 hours.  =  104.

35 + 23 + 23 + 23 + 23 = 5 hours. =  127.

We were looking for if the man earned $127 dollars how many hours would be be working.


He'd be working 5 hours.

Hope this helps (:


5 0
4 years ago
If <img src="https://tex.z-dn.net/?f=%20g%28x%29%3D%5Cfrac%7B1%7D%7Bx%7D%20%20" id="TexFormula1" title=" g(x)=\frac{1}{x} " alt
Ksju [112]

Fill in the given values and simplify.

\dfrac{g(x+h)-g(x)}{h}=\dfrac{\dfrac{1}{x+h}-\dfrac{1}{x}}{h}\\\\=\dfrac{x-(x+h)}{h\cdot x(x+h)}\\\\=\dfrac{-1}{x(x+h)}

4 0
3 years ago
Paula wants to save at least $800 for a trip. Which inequality shows the least amount she must save each month for 9 months to a
ElenaW [278]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Can someone help me with number 3, please
oksian1 [2.3K]

Answer:

E

Step-by-step explanation:

We can see that section E of the graph increases, but unlike section B it is much longer and, therefore, increases more slowly.

Hope this helps friend.

4 0
2 years ago
Read 2 more answers
The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA ba
PSYCHO15rus [73]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.

Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.

xbar = $1,465,752

SD = $1,346,046.2

lower bound of confidence interval ________

upper bound of confidence interval _______

Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.

xbar = $1,371,191

SD = $1,130,666.5

lower bound of confidence interval _________

upper bound of confidence interval. ________

Answer:

Question 1:

lower bound of confidence interval = $1,124,027

upper bound of confidence interval = $1,807,477

Question 2:

lower bound of confidence interval = $1,081,512

upper bound of confidence interval = $1,660,870

Step-by-step explanation:

Question 1:

The sample mean salary of 62 couches is

 \bar{x} = 1,465,752

The standard deviation of mean salary is

 s = 1,346,046.2

The confidence interval for the mean salary of all basketball coaches is given by

 $ CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where \bar{x} is the sample mean, n is the sample size, s is the sample standard deviation and  t_{\alpha/2} is the t-score corresponding to a 95% confidence level.  

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 62 - 1 = 61

From the t-table at α = 0.025 and DoF = 61

t-score = 1.999

So the required 95% confidence interval is  

CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (\frac{1,346,046.2}{\sqrt{62} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (170948.04 ) \\\\CI = 1,465,752 \pm 341,725 \\\\LCI = 1,465,752 - 341,725 = 1,124,027 \\\\UCI = 1,465,752 + 341,725 = 1,807,477\\\\

Question 2:

After removing the Coach Krzyzewski's salary from the data

The sample mean salary of 61 couches is

\bar{x} = 1,371,191

The standard deviation of the mean salary is

s = 1,130,666.5

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 61 - 1 = 60

From the t-table at α = 0.025 and DoF = 60

t-score = 2.001

So the required 95% confidence interval is  

CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (\frac{1,130,666.5}{\sqrt{61} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (144767 ) \\\\CI = 1,371,191 \pm 289,678.8 \\\\LCI = 1,371,191 - 289,678.8 = 1,081,512 \\\\UCI = 1,371,191 + 289,678.8 = 1,660,870\\\\

6 0
3 years ago
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