Answer:
<h2>
60 cm^2</h2>
Solution,
Let ,
a = 13
b = 13
c= 10
then,
s = a + b + c /2
= 13 + 13 + 10 / 2
= 36/2
= 18
Now,
Area of triangle:
![\sqrt{s(s - a)(s - b)(s - c)}](https://tex.z-dn.net/?f=%20%5Csqrt%7Bs%28s%20-%20a%29%28s%20-%20b%29%28s%20-%20c%29%7D%20%20)
![\sqrt{18(18 - 13)(18 - 13)(18 - 10)}](https://tex.z-dn.net/?f=%20%5Csqrt%7B18%2818%20-%2013%29%2818%20-%2013%29%2818%20-%2010%29%7D%20)
![\sqrt{18 \times 5 \times 5 \times 8}](https://tex.z-dn.net/?f=%20%5Csqrt%7B18%20%5Ctimes%205%20%5Ctimes%205%20%5Ctimes%208%7D%20)
![\sqrt{3600}](https://tex.z-dn.net/?f=%20%5Csqrt%7B3600%7D%20)
![60 \: {cm}^{2}](https://tex.z-dn.net/?f=60%20%5C%3A%20%20%7Bcm%7D%5E%7B2%7D%20)
Hope this helps ....
Good luck on your assignment...
Answer:
93
the median is the middle of the data set
Step-by-step explanation:
I found the answer at another website plus wanna get exposed little boys yall aint girls
Answer:
≈ 18.3 m²
Step-by-step explanation:
The shaded area (A) is calculated as
A = area of sector - area of right triangle
area of sector = area of circle × fraction of circle
A = πr² × ![\frac{90}{360}](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7B360%7D)
= π × 8² ×
= 64π ×
= 16π m²
area of triangle =
× 8 × 8 = 4 × 8 = 32 m²
shaded area is then
A = 16π - 32 ≈ 18.3 m² ( to the nearest tenth )
Answer:
i think is 3/2. im no really sure