Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
I hope this helps you
6y=13-2x
y=13-2x/6
y=13/6-1/3x
Answer:
idk hbu
Step-by-step explanation:
Step-by-step explanation:
it's the square equal to the equivalent equation to equal 5 673y
Answer:
43.35pi m cubed
Step-by-step explanation:
Volume of a cylinder
= pi r^2 h
Where r = radius
h = height
Given r = 1.7m and
h = 15m
Volume = pi x (1.7)^2 x 15
= pi x 1.7 x 1.7 x 15
Multiply through
Volume = 43.35 pi m cubed
