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kotykmax [81]
3 years ago
14

The equation of a parabola is shown.

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0
The axis of symmetry for this parabola is the x-axis. The general form of the equation is:
4p(x-h) = (y-k)^2
where the focus has the coordinates of (h+p,k)

Manipulating the given equation to the general form:
4(1/3)(x-7)^2 = (y - 0)^2

Therefore the coordinates of the focus is:
(7+(1/3),0)

The answer is A.) (71/3,0)


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Can someone please answer this question please answer it correctly and please show work please help me I need it
I am Lyosha [343]

Answer:

the answer to this question is the number 8

5 0
3 years ago
EASY BRAINLIEST ANSWER ASAP!!
elena-14-01-66 [18.8K]

Answer:

  1. (0, 4)
  2. (-1, 16/ 3)
  3. (-9/ 2, 10)

Step-by-step explanation:

In an ordered pair the term before the comma is the x variable and the term after the comma is the y variable.

1.

4x + 3y = 12 . . . . . .(0, _)

here were given the x variable

finding the other term

4× 0 + 3y = 12

3y = 12

y = 4

therefore the ordered pair is <u>(0, 4) </u>

2.

. . . . . . . (-1, _)

here were given the x variable

4 × -1 + 3y = 12

3y = 12 + 4

3y = 16

y = 16/ 3

ordered pair is <u>(-1, 16/ 3)</u>

3.

. . . . . . . . (_, 10)

here were given the y variable

finding the other term

4x + 3 × 10 = 12

4x + 30 = 12

4x = 12 - 30

4x = -18

dividing both sides by 2

2x = -9

x = -9/ 2

ordered pair is<u> (-9/ 2, 10)</u>

4 0
2 years ago
Describe the varying vegetation regions in Canada
pantera1 [17]

Answer: Canada Vegetation

Forests are primarily mixes of white and black spruce, lodgepole pine, balsam poplar, paper birch and trembling aspen. Common understorey plants include mountain and green alders, highbush cranberry, wild rose, Canadian buffalo berry and reed grass, fireweed, lingonberry, twinflower and feather mosses.

8 0
2 years ago
Read 2 more answers
Which comparisons are true? Choose all that apply. A. 7.34 &gt; 7.304 B. 1.628 &gt; 1.63 C. 4.05 &lt; 4.055 D. 9.103 &lt; 9.13 E
Nimfa-mama [501]

Answer:

The answers are A, C, & D.

Step-by-step explanation:

A: the 34 would have an imaginary 0 behind it, so then it would become 340, which is greater than 304.

B, C, D: same logic as A

6 0
3 years ago
a shipment of sugar fills 4 1/3 containers. if each container holds 2 1/7 tons of sugar, what is the amount of sugar in the enti
emmasim [6.3K]

To find the answer we need multiply the number of containers by number tons of sugar each container has.

(4 1/3 )*(2 1/7).

To calculate , we need to convert mixed numbers into improper fractions.

4 1/3 = (4*3 +1)/3 = 13/3

2 1/7 = (2*7+1)/7 =15/7

(4 1/3 )*(2 1/7) = (13/3) * (15/7) = (13*5)/7 = 65/7 = 9 2/7 (tons)

Answer: 9 2/7 tons.


8 0
2 years ago
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