∆AQB is isosceles, so ∠QAB = ∠QBA.
The sum of vertex angles of ∆ABC is 180° so you have
... ∠QAB + ∠QCB + (∠QBC + ∠QBA) = 180°
Substituting what we know ...
... ∠QAB + 52° + (28° + ∠QAB) + 180°
... 2∠QAB = 100°
... ∠QAB = 50°
Because PQ is parallel to BC, ∠APQ = ∠ABC = 50° + 28°
... ∠APQ = 78°
1.5, 2
When reflecting across the y-axis, the y in (x, y) stays the same but the x's sign is changed to the opposite.
It could be 10.11 10.12 10.13 10.14
as long as the number next to the one is less than five it will become 10.1
Orange to the left column in the South Pole next to the whale