First we already know that he makes 200 dollars a month at the bowling alley so we can do 500-200 and he would need to 300 dollars from delivering newspapers. Then we need to divide 300 by 5 to see how many hours he needs to work and we would get 60. That means the answer is he would have to deliver newspapers for 60 hours
Answer:
520
Step-by-step explanation:
0.52 as a percent is 52%. 52% of 1000 is 520.
![\left[\begin{array}{ccc}2&6&3\\-5&1&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%266%263%5C%5C-5%261%264%5Cend%7Barray%7D%5Cright%5D)
R1 ÷ 2 = ![\left[\begin{array}{ccc}1&3&1.5\\-5&1&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261.5%5C%5C-5%261%264%5Cend%7Barray%7D%5Cright%5D)
R2 ÷ -5 = ![\left[\begin{array}{ccc}1&3&1.5\\1&-0.2&-0.8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261.5%5C%5C1%26-0.2%26-0.8%5Cend%7Barray%7D%5Cright%5D)
R2: R1 - R2 = ![\left[\begin{array}{ccc}1&3&1.5\\0&3.2&2.3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261.5%5C%5C0%263.2%262.3%5Cend%7Barray%7D%5Cright%5D)
R2 ÷ 3.2 = ![\left[\begin{array}{ccc}1&3&1.5\\0&1&0.71875\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261.5%5C%5C0%261%260.71875%5Cend%7Barray%7D%5Cright%5D)
R1: R1 - 3R2 = ![\left[\begin{array}{ccc}1&0&0.65625\\0&1&0.71875\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260.65625%5C%5C0%261%260.71875%5Cend%7Barray%7D%5Cright%5D)
Answer: x = 0.65625, y = 0.71875
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The length of a training track running around the field is
Step-by-step explanation:
From the question we are told that
The length of the field is ![L= 93 \ m](https://tex.z-dn.net/?f=L%3D%2093%20%5C%20m)
The width of the field is ![W = 61 \ m](https://tex.z-dn.net/?f=W%20%3D%20%2061%20%5C%20m)
The length of the two semicircle is mathematically evaluated as
![A = 2 * \pi * \frac{W}{2}](https://tex.z-dn.net/?f=A%20%20%3D%202%20%2A%20%5Cpi%20%20%2A%20%5Cfrac%7BW%7D%7B2%7D)
substituting values
![A = 2 *3.142 * \frac{61}{2}](https://tex.z-dn.net/?f=A%20%20%3D%202%20%2A3.142%20%20%2A%20%5Cfrac%7B61%7D%7B2%7D)
![A = 191.54 \ m](https://tex.z-dn.net/?f=A%20%20%3D%20191.54%20%5C%20m)
Now the length of a training track running around the field is
![Z = A + 2 L](https://tex.z-dn.net/?f=Z%20%3D%20A%20%2B%20%202%20L)
substituting values
![Z = 191.54 + 2 (93)](https://tex.z-dn.net/?f=Z%20%3D%20191.54%20%2B%20%202%20%2893%29)
![Z = 377.54 \ m](https://tex.z-dn.net/?f=Z%20%3D%20377.54%20%5C%20m)