3 years ago

I need help on 33 please help

Mathematics

1 answer:

lyudmila [28]3 years ago

7 0

Uhh I think it a carrot

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A project has an initial cost of $60,000, expected net cash inflows of $14,000 per year for 9 years, and a cost of capital of 14

vredina [299]

Answer:

Step-by-step explanation:

60,000 + 14,000

ANS 14%

ANSWER: 74

6 0

3 years ago

Segment FG begins at point F(-2, 4) and ends at point G (-2, -3). Segment FG is translated by (x, y) → (x – 3, y + 2) and then r

Mariana [72]

Answer:

The length of the segment F'G' is 7.

Step-by-step explanation:

From Linear Algebra we define reflection across the y-axis as follows:

$(x',y')=(-x, y)$ , $\forall\, x, y\in \mathbb{R}$ (Eq. 1)

In addition, we get this translation formula from the statement of the problem:

$(x',y') =(x-3,y+2)$ , $\forall \,x,y\in \mathbb{R}$ (Eq. 2)

Where:

$(x, y)$ - Original point, dimensionless.

$(x', y')$ - Transformed point, dimensionless.

If we know that $F(x,y) = (-2, 4)$ and $G(x,y) = (-2,-3)$ , then we proceed to make all needed operations:

Translation

$F''(x,y) = (-2-3,4+2)$

$F''(x,y) = (-5,6)$

$G''(x,y) = (-2-3,-3+2)$

$G''(x,y) = (-5,-1)$

Reflection

$F'(x,y) = (5, 6)$

$G'(x,y) = (5,-1)$

Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:

$F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}$

$F'G' = 7$

The length of the segment F'G' is 7.

8 0

3 years ago

Sec^2 (pi/2 - x) * [sin^2 (x) - sin^4 (x)]

Bad White [126]

Answer:

Explanation:

Identity: sec2θ=1+tan2θ

sec2(π2−x)−1=1+tan2(π2−x)−1

=tan2(π2−x)

Identity: tan(π2−θ)=cotθ

=cot2x

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3 years ago

Find the distance and midpoint between (3,6) and (5,11)

zepelin [54]

Answer:

((3+5)/2,(6+11)/2)=(4,8.5)

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3 years ago

Help please thank you

crimeas [40]

10/30 or you can symlafife

5 0

3 years ago