Because y varies inversely as x, therefore

where k = constant.
When x = 6, y = 2.5. Ther efore

Cross multiply.
k = 6 x 2.5 = 15
The equation is

When x = 4, obtain

Answer: a. 3.75
Answer:
0.50 x 4.50 = 69.42.00 and 22 = 47.420.00
Step-by-step explanation:
47.420.00
Answer:
6
Step-by-step explanation:
Find the area of both triangles inside the bigger triangle and add them together.
Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:
a² + b² = c²
2² + b² = 3²
4 + b² = 9
5 = b²
2.2 ≈ b
Calculate the area of the smaller triangle:
1/2(bxh)
1/2(2 x 2.2)
1/2(4.4)
2.2
Calculate the area of the bigger triangle:
<em>We know that the longer leg is 3.8 units because we were able to subtract the length of the smaller triangle's leg from 6.
</em>
1/2(bxh)
1/2(2 x 3.8)
1/2(7.6)
3.8
Add both areas to find the area of the largest triangle:
3.8 + 2.2 = 6
Answer:
A. The first graph
Step-by-step explanation:
When you graph these two equations on a graphing calc, you should be able to see one dotted line and one solid, as well as the solutions being mostly in the 1st quadrant.
N = d - 5
2n/(d + 16) = n/d - 1/3 n/d
2n/(d + 16) = 2/3 n/d Divide by 2n
1 / (d + 16) = 1/3 d
Here's the tricky part.
d + 16 = 3d the two denominators are equal. the numerators are both 1.
16 = 2d
d = 8
so the numerator is d - 5
n = 8 - 5
n = 3
Let's see if it checks out.
n = 3
d = 8
2*3 = 6
8 + 16 = 24
New fraction 6/24 = 1/4
(3/8 - 1/3 ) = 1/8
3/8 - 1/8 = 1/4 so it checks with the original conditions put on it.