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Ulleksa [173]
3 years ago
8

What are the solutions of the equation x4 + 95x2 – 500 = 0? Use factoring to solve. x = plus-or-minus StartRoot 5 EndRoot and x

= ±10 x = plus-or-minus i StartRoot 5 EndRoot and x = ±10i x = plus-or-minus StartRoot 5 EndRoot and x = ±10i x = plus-or-minus i StartRoot 5 EndRoot and x = ±10
Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

<em>* x ⇒ plus-or-minus StartRoot 5 EndRoot and ±10i *</em>

Step-by-step explanation:

Through factorization;

x^4 + 95x^2 – 500 = 0, ⇒ <em>u^2 ⇒ x^2</em>,

u^2 + 95u - 500 = 0, ⇒<em> factors of -500; -25, 20, -50 * 10, -2 * 250, -5 * 100...</em>

( u )^2 + ( - 5 + 100 ) + ( - 5 * 100 ) = 0,

( u - 5 )( u + 100 ) = 0,

<em>u = 5, and y = - 100</em>

Substitute u back into format x^2;

u = x^2, 5 = x^2, | x | = √5 ⇒ <em>x = - / + √5,</em>

u = x^2, - 100 = x^2, | x | = √- 100 ⇒ <em>x = - / + 10i</em>

<em>* Answer: x ⇒ plus-or-minus StartRoot 5 EndRoot and ±10i *</em>

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