Answer:
By excluding (10, 15), a better description can be given for the data set.
Step-by-step explanation:
Overall, this data seems to suggest a decreasing trend. The value (10, 15) is an outlier; if we remove it, the trend appears to be stronger. Thus if we exclude this value we can give a better description of the data set.
0.03x+0.06 (6500-x)=225
Solve for x
0.03x+390-0.06x=225
0.03x-0.06x=225-390
-0.03x=-165
X=165÷0.03
X=5500 invested at 3%
6500-5500=1000 invested at 6%
For this case we can model the problem as a rectangle triangle.
We have:
Length of the sides of the triangle.
We want to find:
Length of the hypotenuse.
Using the Pythagorean theorem we have:
Answer:
She is:
miles far from her starting point
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
