What is the solution to 2 In x = 4 In 2? x=
1 answer:
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I have added a screenshot with the complete question.
Answer:
At least 7 more students need to sign up for the field trip to be scheduled
Explanation:
Assume that the least number of students remaining to register for the trip to be scheduled is x.
total number of students = students who already registered + x
We are given that, the least number of students required for this trip is 30. This means that:
total number of students ≥ 30
Now, we know that 23 students already registered.
The inequality now is:
x + 23 ≥ 30
x ≥ 30 - 23
x ≥ 7
This means that at least 7 more students must register for the trip to be scheduled.
Hope this helps :)
Answer:
At least 7 more students need to sign up for the field trip to be scheduled
Explanation:
Assume that the least number of students remaining to register for the trip to be scheduled is x.
total number of students = students who already registered + x
We are given that, the least number of students required for this trip is 30. This means that:
total number of students ≥ 30
Now, we know that 23 students already registered.
The inequality now is:
x + 23 ≥ 30
x ≥ 30 - 23
x ≥ 7
This means that at least 7 more students must register for the trip to be scheduled.
Hope this helps :)
Answer: A & B are the same answer --> 96, max
<u>Step-by-step explanation:</u>
Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:
- If m > n, then there is no H.A.
- If m = n, then y = coefficient of numerator ÷ coefficient of denominator
- If m < n, then y = 0
In the given problem, m = 1 and n = 1 so the H.A. is:
This is the maximum number of moose that the forest can sustain at one time.