V1=30km/hr
v2=20km/hr
v=2v1v2/(v1+v2)
=2*30*20/(30+20)
=24km/hr
For this case we have the following function:

By the time the stone is thrown, x = 0.
We must evaluate this value of x in the function.
We have then:
Answer:
The height of the stone at the time is thrown is given by:
h (0) = 15 meters



with that template in mind, let's see,

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.
the smaller A is, the wider it opens, the larger it is, the more it shrinks.
After 2 weeks:
15+3(2)=15+6= $21
After 5 weeks:
15+3(5)=15+15= $30
After 10 weeks:
15+3(10)=15+30= $45
Hope this helps