<span>Let C represent the total cost (in dollars),
and let S represent the amount of sugar (in tons) transported
equation:
C(s) = </span><span>225s + 7500
</span><span>find the total cost to transport 11 tons of sugar.
</span>C(11) = 225(11) + 7500
C(11) = 2475 + 7500
C(11) = 9975
hope it helps
Answer:
(x, y) = (0, -2248)
Step-by-step explanation:
<u>Substitution</u>
Substitute for y:
300x -2248 = 350x -2248
0 = 50x . . . . . . . . add 2248-300x to both sides
x = 0
y = 300·0 -2248
The solution is (x, y) = (0, -2248).
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<u>Elimination</u>
Subtract the first equation from the second.
(y) -(y) = (350x -2248) -(300x -2248)
0 = 50x
x = 0
y = 300·0 -2248
The solution is (x, y) = (0, -2248).
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<em>Additional comment</em>
If you think for a bit about what the graph looks like, you realize both lines cross at their y-intercept, (0, -2248). That point of intersection is the solution to the system of equations.
Answer : Distance between the ships to the nearest miles = 106.03 ≈ 106 mi.
Explanation :
Since we have shown in the figure below :
a=70 mi.
b=52 mi.
c=x mi.
So, we use the cosine rule , which states that
So, c = x= 106.03 mi.
Hence, distance between the ships to the nearest miles = 106.03 ≈ 106 mi.
D . Is the correct answer
"Joint variation<span>" means "directly, but with two or more variables". Thus, we write as follows:
j </span>α gv
<span>
We insert proportionality constant k, to change it to equality.
j = kgv
We solve k,
1 = k (4)(3)
k =1/12
j = gv/12
j = 8(11)/12
j = 22/3</span>
