All categories

3 years ago

Solve Inequality -14x > -112

Mathematics

2 answers:

den301095 [7]3 years ago

8 0

Answer:

x <8

Step-by-step explanation:

-14x > -112

Divide each side by -14. Remember that flips the inequality

-14x/-14 < -112/-14

x <8

Nitella [24]3 years ago

4 0

Answer:

$\large\boxed{x$

Step-by-step explanation:

$-14x>-112\qquad\text{change the signs}\\\\14x$

<, > - open circle

≤, ≥ - closed circle

<, ≤ - draw the line to the left

>, ≥ - draw the line to the right

You might be interested in

The company you work for has a policy of paying overtime for all hours worked in excess of 40 per week you worked 8 hours each d

makvit [3.9K]

you would have earned 2 hours worth

5 0

3 years ago

Can someone help me please?

MAVERICK [17]

Good. I hope you get locked, most mainly banned. Nobody needs you, “FrIsK”

4 0

3 years ago

How do you do this question?

AfilCa [17]

<h3>4 Answers: A, B, C, D</h3>

=======================================================

Explanation:

f(x) is continuous when x >= 1. The only discontinuity for f(x) is when x = 0, but 0 is not part of this interval.

f(x) is positive for any valid x value in the domain since x^6 is always positive. In general, x^n is positive for all x when n is any even number.

f(x) is decreasing. You can see this through a table of values or through a graph. For anything in the form 1/(x^k), it will be a decreasing function because x^k gets larger, so 1/(x^k) gets smaller, when x goes to infinity.

--------------------

The conditions to use the integral test have been met. So we have to see if $\displaystyle \int_1^{\infty}f(x)dx$ converges or not.

Let's integrate and find out

$\displaystyle \int \frac{1}{x^6} dx = \int x^{-6} dx\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{1+(-6)}x^{-6+1}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{-5}x^{-5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5}*\frac{1}{x^5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5x^5}+C\\\\$

So we have

$\displaystyle g(x) = \int f(x) dx\\\\\\\displaystyle g(x) = \int \frac{1}{x^6} dx\\\\\\\displaystyle g(x) = -\frac{1}{5x^5}+C\\\\\\$

Meaning that,

$\displaystyle \int_{a}^{b} f(x) dx = g(b)-g(a)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = \left(-\frac{1}{5b^5}+C\right)-\left(-\frac{1}{5a^5}+C\right)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = -\frac{1}{5b^5}+\frac{1}{5a^5}\\\\\\$

If we plug in a = 1 and apply the limit as b approaches positive infinity, then the expression $-\frac{1}{5b^5}+\frac{1}{5a^5}$ will turn into $\frac{1}{5}$