The algebraic equation used to answer this question is:
3d + 4(1/2d) = 56.5
This is because he ran d, the distance, three times that week. For the rest of the four days, he ran 1/2 the distance, or half d.
To find the answer, you first distribute:
3d + 2d = 56.5
Add like terms:
5d = 56.5
Divide both side by 5:
5d/5 = 56.5/5
d = 11.3
On the first three days, Luke jogged 11.3 miles. On the remaining days, where he jogged 1/2d, Luke jogged 5.65 miles.
Hope this helps!
Answer:
10x+9
Step-by-step explanation:
You first have to multiply 3 into the parenthesis because you have to use distributive property.
Once you do that you get 3x+9+7x.
Combine like terms.
10x+9
Answer:
1) AD=BC(corresponding parts of congruent triangles)
2)The value of x and y are 65 ° and 77.5° respectively
Step-by-step explanation:
1)
Given : AD||BC
AC bisects BD
So, AE=EC and BE=ED
We need to prove AD = BC
In ΔAED and ΔBEC
AE=EC (Given)
( Vertically opposite angles)
BE=ED (Given)
So, ΔAED ≅ ΔBEC (By SAS)
So, AD=BC(corresponding parts of congruent triangles)
Hence Proved
2)
Refer the attached figure
In ΔDBC
BC=DC (Given)
So,
(Opposite angles of equal sides are equal)
So,
So,
(Angle sum property)
x+x+50=180
2x+50=180
2x=130
x=65
So,
Now,
So,
In ΔABD
AB = BD (Given)
So,
(Opposite angles of equal sides are equal)
So,
So,
(Angle Sum property)
y+y+25=180
2y=180-25
2y=155
y=77.5
So, The value of x and y are 65 ° and 77.5° respectively
The 4 is the constant term.
Answer:
x ≥ y + 2
0.50 (x) (x+3) + 2.25 (4) (y) ≤ 50
Step-by-step explanation:
x = width of the car
x+3 = length of the car
y = radius of the car
The width must be at least 2 inches greater than the radius, so:
x ≥ y + 2
The total cost must be no more than $50, so:
0.50 (x) (x+3) + 2.25 (4) (y) ≤ 50
