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grin007 [14]
3 years ago
10

A couch priced at $300 is on sale for 40% off. What is the sale price of the couch?

Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0

Answer: $180

Step-by-step explanation:

Nezavi [6.7K]3 years ago
3 0

Answer:

180

Step-by-step explanation:

300-40% = 180 hshsjsbhshebs

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<) Madison is organizing a 10K race. She is ordering cases of bottled water for the runners.
love history [14]

Answer:

b= 20 • c

b is equalled to how many bottles, which c is equalled to how many cases, since there is no number for how many cases then is just the variable "c".

4 0
3 years ago
1 3/4 - 4/5 <br><br> And how did you solve it plz I don’t know how to subtract fractions :(((
Valentin [98]

Answer:

19/20

Step-by-step explanation:

check the images for an explanation sorry if its hard to understand

8 0
3 years ago
Q1 A ball is thrown upwards with some initial speed. It goes up to a height of 19.6m and then returns. Find (a) The initial spee
lubasha [3.4K]

Answer:

(a)  19.6 ms⁻¹

(b)  2 s

(c)  9.8 ms⁻¹

(d)  4 s

Step-by-step explanation:

<u>Constant Acceleration Equations (SUVAT)</u>

\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Acceleration due to gravity = 9.8 ms⁻².

<h3><u>Part (a)</u></h3>

When the ball reaches its maximum height, its velocity will momentarily be zero.

<u>Given values</u> (taking up as positive):

s=19.6 \quad v=0 \quad a=-9.8

\begin{aligned}\textsf{Using} \quad v^2&=u^2+2as\\\\\textsf{Substitute the given values:}\\0^2&=u^2+2(-9.8)(19.6)\\0&=u^2-384.16\\u^2&=384.16\\u&=\sqrt{384.16}\\\implies u&=19.6\; \sf ms^{-1}\end{aligned}

Therefore, the initial speed is 19.6 ms⁻¹.

<h3><u>Part (b)</u></h3>

Using the same values as for part (a):

\begin{aligned}\textsf{Using} \quad s&=vt-\dfrac{1}{2}at^2\\\\\textsf{Substitute the given values:}\\19.6&=0(t)-\dfrac{1}{2}(-9.8)t^2\\19.6&=4.9t^2\\t^2&=\dfrac{19.6}{4.9}\\t^2&=4\\t&=\sqrt{4}\\\implies t&=2\; \sf s\end{aligned}

Therefore, the time taken to reach the highest point is 2 seconds.

<h3><u>Part (c)</u></h3>

As the ball reaches its maximum height at 2 seconds, one second before this time is 1 s.

<u>Given values</u> (taking up as positive):

u=19.6 \quad a=-9.8 \quad t=1

\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=19.6+(-9.8)(1)\\v&=19.6-9.8\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}

The velocity of the ball one second before it reaches its maximum height is the <u>same</u> as the velocity one second after.

<u>Proof</u>

When the ball reaches its maximum height, its velocity is zero.

Therefore, the values for the downwards journey (from when it reaches its maximum height):

u=0 \quad a=9.8 \quad t=1

(acceleration is now positive as we are taking ↓ as positive).

\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=0+9.8(1)\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}

Therefore, the velocity of the ball one second before <u>and</u> one second after it reaches the maximum height is 9.8 ms⁻¹.

<h3><u>Part (d)</u></h3>

From part (a) we know that the time taken to reach the highest point is 2 seconds.  Therefore, the time taken by the ball to travel from the highest point to its original position will also be 2 seconds.

Therefore, the total time taken by the ball to return to its original position after it is thrown upwards is 4 seconds.

4 0
1 year ago
Jake walked 1 mile in 15 minutes. This week he walked 1 mile in 12 minutes. What is the percent of decrease in Jakes time to wal
dsp73
His time to walk a milk decreased by 20%.
6 0
3 years ago
George had $127 in his checking account on Thursday. He got paid on Friday and deposited $130.00 into his checking account. Then
Pavel [41]

Answer:

The balance on George's checking account is $48.

Step-by-step explanation:

To find the balance on George's checking account after writing the checks, you have to take the initial balance and add the amount he got paid and subtract the amounts of the checks he wrote:

Checking account balance=$127+$130-$167-$42

Checking account balance=$48

According to this, the answer is that the balance on George's checking account is $48.

7 0
3 years ago
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