Answer:
8x² + 11x - 9
Step-by-step explanation:
M - N
= 5x² + 7x - 4 - 1(- 3x² - 4x + 5) ← distribute parenthesis by - 1
= 5x² + 7x - 4 + 3x² + 4x - 5 ← collect like terms
= 8x² + 11x - 9
Answer:
10z+34
Step-by-step explanation:
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.
2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.
3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.
4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.
Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
Are you asking for a name?
M is a subset of u.
Is there something further?
Answer:
given, y≥2x+1 and
y>
2
1
x−1
first, draw the graph for equations y=2x+1 and y=
2
1
x−1
for y=2x+1
substitute y=0 we get, 2x+1=0⟹x=−0.5
substitute x=0 we get, y=1
therefore, y=2x+1 line passes through (0.5,0) and (0,1) as shown in fig.
Hence, y≥2x+1 includes the region above the line.
for y=
2
1
x−1
substitute y=0 we get,
2
1
x−1=0⟹x=2
substitute x=0 we get, y=−1
therefore, y=2x+1 line passes through (2,0) and (0,-1) as shown in fig.
Hence, y>
2
1
x−1 includes the region above the line.
the intersection region is the shaded region as shown in above figure which includes I, II and III quadrants.
Therefore, quadrant IV has no solution please make as brainlelist