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kenny6666 [7]
2 years ago
5

I want a way to solve such a problem​

Mathematics
1 answer:
den301095 [7]2 years ago
6 0
<h3>Answer: Choice A)  11.4</h3>

========================================================

Explanation:

Refer to the table below.

The first step is to find the midpoint of each interval.

To do that, we add up the endpoints and divide by 2. The midpoint of the interval from 2 to 6 is 4 because (2+6)/2 = 8/2 = 4. Repeat these steps for the other intervals to find that the remaining midpoints are: 8, 12, 16, 20.

Overall, the midpoints from top to bottom are 4, 8, 12, 16, 20

Note how the midpoints are incrementing by 4 each time, which is the same distance between each successive left endpoint (and right endpoint endpoints as well).

Let's say m represents the set of midpoints which I'll form in the third column. Multiply the frequency column f by each corresponding midpoint m. The result fm forms the fourth column.

Add up everything in that fourth column to get 1140. We then divide that by the sum of the frequencies (100) to get 1140/100 = 11.4 which is the final answer. The average weight is 11.4 pounds.

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You spin each spinner once. You get $50 if you spin a 2 and a vowel. You get $25 if you spin a 2 and a consonant. You get $5 if
Tom [10]

The expected value of the game is $8.75.

----------------------

  • The expected value is the <u>sum of each outcome multiplied by it's probability</u>.
  • A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.

  • The probability of spinning a 2 and a vowel is: \frac{1}{4} \times \frac{2}{8} = \frac{2}{32}.
  • Thus, \frac{2}{32} probability of getting $50.

  • The probability of spinning 2 and a consonant is: \frac{1}{4} \times \frac{6}{8} = \frac{6}{32}
  • Thus, \frac{6}{32} probability of getting $25.

  • The probability of spinning 1 and a vowel is: \frac{3}{4} \times \frac{2}{8} = \frac{6}{32}.
  • Thus, \frac{6}{32} probability of getting $5.

  • 32 - (6 + 6 + 2) = 18, thus, \frac{18}{32} probability of earning $0.

The expected value is:

E = \frac{2}{32}(50) + \frac{6}{32}(25) + \frac{6}{32}(5) + \frac{18}{32}(0)

E = \frac{100 + 150 + 30}{32}

E = \frac{280}{32}

E = 8.75

The expected value of this game is of $8.75.

A similar problem is given at brainly.com/question/24961584

8 0
2 years ago
Yo which set or sets does the Number 37 belong?
Tresset [83]
It is a whole number
3 0
3 years ago
Math question I need help with
Greeley [361]
F(x) = (x - 4) (x^2 + 4) would be your answer.
4 0
2 years ago
There are 15 students on a yearbook committee. 40% of the students are females. How many students on the committee are males?
Andrei [34K]

Answer:

9 students on the committee are males

Step-by-step explanation:

As per the statement:

There are 15 students on a yearbook committee.

⇒Total students on a yearbook committee = 15

⇒\text{Male students} +\text{Female students} = 15     ....[1]

It is given that:

40% of the students are females

⇒\text{Female students} = \frac{40}{100} \cdot 15 = 6

Substitute in [1] we have;

\text{Male students} + 6 = 15

Subtract 6 from both sides we have;

\text{Male students}= 9

Therefore, 9 students on the committee are males

8 0
3 years ago
Read 2 more answers
3. Bob the Builder wants to earn an annual rate of 10% on his investments,
mamaluj [8]

Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

After t years, the total amount of money is:

T = E + P

In this question:

Rate of 10%, so I = 0.1.

9 months, so t = \frac{9}{12} = 0.75

How much should he pay for a note that will be worth $3,000 in 9 months?

We have to find P for which T = 3000. So

T = E + P

3000 = E + P

E = 3000 - P

Then

E = P*I*t

3000 - P = P*0.1*0.75

1.075P = 3000

P = \frac{3000}{1.075}

P = 2790.7

He should pay $2,790.7.

8 0
3 years ago
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