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Rama09 [41]
2 years ago
6

Find the Zeros: 0=2(x+2)^2-5

Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
5 0

Answer:

no solution

Step-by-step explanation:

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Can you please help me solve this equation?
TiliK225 [7]

Answer: ((T/(2pi))^2)g

Step-by-step explanation: just solve for L

4 0
3 years ago
I need help i don’t understand
ch4aika [34]

9514 1404 393

Answer:

  A) J(-3, 1), ...

Step-by-step explanation:

All of the answer choices list point J' first, so it is convenient to use that as an example.

Point J on the given graph has coordinates (x, y) = (3, 2). The x-coordinate is 3 because the point is 3 units to the right of the y-axis.

The problem statement tells you to translate this point 6 units to the left. When you move it 6 units left, it will move left 3 units to the y-axis, then left 3 more units to have an x-coordinate of 3 -6 = -3. That is, each unit of movement to the left subtracts 1 from the x-coordinate. The x-coordinate of J is 3, so the final point J' will have an x-coordinate of 3 - 6 = -3.

At this point, you have enough information to make the correct answer selection. Only one answer choice has the x-coordinate of J' as -3.

__

The other coordinates are translated using similar logic. The y-coordinate of J is 2. Translating it down 1 unit subtracts 1 from the y-coordinate to make it be 2 -1 = 1. Then the coordinates of J' are (-3, 1).

We write the translation rule as ...

  (x, y) ⇒ (x -6, y -1)

This means the coordinates of each translated point have 6 subtracted from the original x-coordinate, and 1 subtracted from the original y-coordinate. The other coordinates of the figure are ...

  I(2, 4) ⇒ I'(2 -6, 4 -1) = I'(-4, 3)

  H(5, 5) ⇒ H'(5 -6, 5 -1) = H'(-1, 4)

  G(4, 1) ⇒ G'(4 -6, 1 -1) = G'(-2, 0)

3 0
3 years ago
ASAP!!! PLEASE HELP & EXPLAIN.
Vika [28.1K]

Answer:

B

Step-by-step explanation:

the domain of a graph consists of all the input values shown on the x-axis.

so because the only parts shown on the x axis are 6 and -6 that is the answer!

hope this helps!

4 0
2 years ago
X≥1 x≤7 y≥-1/3x+6
Goshia [24]

Answer:

Step-by-step explanation:

i am unsure of what you actually need, but i want to help you.

if you were to set the boundaries of the feasibility region it would be as follows:

as points

A(1, 17/3)   B(7, 11/3)   C(7, infinity)   D(1, infinity)

as graphs

y=-1/3x+6 where 1≤x≤7

x=1

x=7

7 0
3 years ago
Read 2 more answers
Write an equation of the circle with center (-7, 4) and radius 8.
Stels [109]

answer

(x+7)^2 + (y-4)^2 = 64

set up equation

the equation of a circle is (x - h)^2 + (y - k)^2 = r^2

where h is the center x coordinate and k is the center y coordinate

values

from the point (-7,4) we know that h = -7 and k = 4

since the radius is 8, r^2 = 8^2 = 64

plug in values

now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2

(x - h)^2 + (y - k)^2 = r^2

(x - (-7))^2 + (y-4)^2 = 64

(x+7)^2 + (y-4)^2 = 64

7 0
3 years ago
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