I think it is -4y + y
I don't know if it is correct, but I'm pretty sure it is.
66 x 3 = 198
198 + 2 = 200
200 / 3
As an improper fraction, anyway. 66 2/3 is already *technically* a fraction.
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
1
The correct option is C
2
The correct option is C
3
The correct option is A
4
The correct option is B
Step-by-step explanation:
From the question we are told that
The population mean is
The standard deviation is
The sample size is
The sample mean is
Generally
The null hypothesis is
The alternative hypothesis is
Given that the null hypothesis is true then the distribution of sample means , from a sample size of 36 is mathematically represented as
=>
According to the Central Limit Theorem the test stated in the question is approximately normally distributed if the sample size is sufficiently large so given that the sample size is large n = 36
Then the test is normally distributed and hence the standard deviation is 15
Generally the standard error of mean is mathematically represented as
=>
=>
Generally the approximate probability of observing a sample mean of 105.1 or more is mathematically represented as
=>
From the z-table (reference calculator dot net )
So
Answer:
50 is the final answer.
Step-by-step explanation:
5+15(3)
5+45
50.