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Marysya12 [62]
3 years ago
9

If line GH and line JK form a right angle and intersect at P are they perpendicular?

Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0

Yes

If they form 90 degrees, they are perpendicular

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Find the center and radius of the sphere whose equation is given by x2+y2+z2−2x−4y+8z+17=0x2+y2+z2−2x−4y+8z+17=0.
Vedmedyk [2.9K]
We know that
the equation of a sphere is
(x-h)²+(y-k)²+(z-l)²=r²
where (h,k,l) is the center and r is the radius

we have
x²+y²+z²<span>−2x−4y+8z+17=0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²+2x)+(y²-4y)+(z²+8z)=-17
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=-17+1+4+16
(x²+2x+1)+(y²-4y+4)+(z²+8z+16)=4

Rewrite as perfect squares

(x+1)²+(y-2²)+(z+4)²=4

(x+1)²+(y-2²)+(z+4)²=2²

the center is the point (-1,2,-4) and the radius is 2 units




4 0
2 years ago
Simplify <br> 14z+12y3+10y3+7y3
Alona [7]

Answer:

14z+29y^3

Step-by-step explanation:

14z+12y^3+10y^3+7y^3

Combine like terms

14z+29y^3

4 0
3 years ago
Read 2 more answers
Please help me!<br><br> Decrease £40 by 10%
Alekssandra [29.7K]

Answer:

36

Step-by-step explanation:

40 * .10 = 4

40-4 = 36

6 0
2 years ago
Read 2 more answers
2950 - 125 - 50 =<br> I dont resly understand
Masja [62]

Answer:

2950 - 125 - 50 \\ =  2950 - (125 + 50) \\  = 2950 - 175 \\  =  \boxed{2775}

<h3><u>2775</u> is the right answer.</h3>
7 0
2 years ago
a 18 ft tall statue standing next to a globe casts a 12 ft shadow. Of the globe casts a shadow that is 2 ft ling, then how tall
Igoryamba
<h3>Answer:</h3>

3 ft

<h3>Step-by-step explanation:</h3>

The statue's height is 1.5 times the length of its shadow, so we expect the same relationship for the globe.

... 1.5 × 2 ft = 3 ft

_____

<em>Comment on the problem</em>

As a practical matter, with the sun high enough in the sky to cast a shadow shorter than the object's height, it will be quite difficult to measure the length of the shadow of the point at the top of the globe. The shadow of other parts of the globe will interfere.

4 0
3 years ago
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