If line GH and line JK form a right angle and intersect at P are they perpendicular?

I have a math question I need help answering.

aniked [119]

The answer should be $21,840.50

Explanation:

20000*1.045=a (first year)
a*1.045=b (second year)
b = 21840.5

6 0

3 years ago

Which of the sums below can be expressed as 6(3 + 9)? (3 points) 18 + 54 18 + 9 9 + 15 6 + 54

vitfil [10]

6*3 = 18

6*9 = 54

so 18 +54 is the correct answer

7 0

3 years ago

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1. Which description best describes the solution to the following system of equations?

Alisiya [41]

1. The best answer is A since a solution is where 2 lines intersect. Whether or not they intersect the x or y axis is completely irrelevant (so is whether they intersect the origin).

2. y=-x+5
-x+5=1/2x+2
-x+3=1/2x
3=3/2x
2=x

y=-(2)+5
y=3

Answer: (2,3)

3. It seems like the lines are completely on top of each other (coinciding) so there are infinitely many solutions.

6 0

3 years ago

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Nadine and Calvin are simplifying the expression (StartFraction r Superscript negative 5 Baseline s Superscript negative 3 Basel

Nat2105 [25]

Answer:

Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step

That is $(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4}$ Calvin's step is the correct step.Because this is the correct way to do simplify the rational expression. And also because Nadine made a blender mistake in her operations in step

Step-by-step explanation:

Given that Nadine and Calvin are simplifying the expression (StartFraction r Superscript negative 5 Baseline s Superscript negative 3 Baseline Over r Superscript 8 Baseline s Superscript negative 2 Baseline EndFraction) Superscript negative 4

Their expression can be written as below

$(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}$

Nadine's first step is to simplify the expression is to raise the numerator and denominator to the power of 4 to get StartFraction r Superscript negative 20 Baseline s Superscript negative 12 Baseline Over r Superscript 32 Baseline s Superscript 8 Baseline EndFraction

That is $\frac{r^{20}s^{12}}{r^{-32}s^8}$

Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4

That is $r^{-13}s^{-1}$

Now simplify the given expression to check whose step is correct:

$(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}$

$=(r^{-5}s^{-3}r^{-8}s^{2})^{-4}$ ( using the property $\frac{1}{a^m}=a^{-m}$ )

$=(r^{-5-8}s^{-3+2})^{-4}$

$=(r^{-13}s^{-1})^{-4}$

Therefore $(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4}$

Therefore Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step.

That is $(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4}$ Calvin's step is the correct step .Because this is the correct way to do simplify the rational expression.And also because Nadine made a blender mistake in her operations in step

6 0

3 years ago

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Y2/y2−6y = 4(3−2y)/y(6−y)

Komok [63]

Solutions are 2 and 6.

Step-by-step explanation:

Step 1: Solve for y to find the solutions.

⇒ y²/y² - 6y = 4(3 - 2y)/y(6 - y)

⇒ y²/y² - 6y = 12 - 8y/6y - y²

⇒ y²/y² - 6y = -12 + 8y/y² - 6y (Taking the negative side out from 6y - y²)

⇒ y² = -12 + 8y (Both denominators are cancelled out)

⇒ y² - 8y + 12 = 0

⇒ y² - 6y - 2y + 12 = 0

⇒ y(y - 6) - 2(y - 6) = 0

⇒ (y-6)(y - 2) = 0

⇒ y = 2, 6

8 0

3 years ago