Answer:
d=√73=8.544
Step-by-step explanation:
Find distance (d) between market (0,8) , court house(6,5) and library(6,-1)
d between two pint is :
d=√(x2-x1)²-(y2-y1)²
d between market and court house:
d=√(6-0)²+(5-8)²
d=√36+9=√45 = 6.7082 ≅6.71 rounded to the nearest hundredths
d between courthouse and the library:
d=√(6-6)²+(-1-5)²
d=√36=6
the distance that Runner A ran=6.71+6=12.71
the distance from the library to the school:
d=√(6-(-2))²+(-1-(-4))²
d=√8²+3²
d=√64+9
d=√73=8.544 ( rounded to the nearest hundredth)
Runner B went 8.544 further than Runner A before stopping at school ( which is the distance between the library and the school.
It’s the first graph or A
The answer would be 24 yards. This would be 24 because 3 feet equal one yard so 3/72 is 24 or 24•3.
Use the Pythagorean Theorem:
a^2 + b^2= c^2
a= one side= 68 mi
b= second side= 80 mi
c= hypotenuse= Greenville to Columbia mi
a^2 + b^2= c^2
68^2 + 80^2= c^2
square each number
4,624 + 6,400= c^2
11,024= c^2
take square root of both sides
104.995 mi= c
ANSWER: The distance from Greenville to Columbia is 104.995 miles (rounded to 105 miles).
Hope this helps! :)
Check the picture below
now, <span>26°35' is just 26bdegrees and 35 minutes
your calculator most likely will have a button [ </span><span>° ' " ] to enter degrees and minutes and seconds
there are 60 minutes in 1 degree and 60 seconds in 1 minute
so.. you could also just convert the 35' to 35/60 degrees
so </span>
![\bf 26^o35'\implies 26+\frac{35}{60}\implies \cfrac{1595}{60}\iff \cfrac{319}{12} \\\\\\ tan(26^o35')\iff tan\left[ \left( \cfrac{391}{12} \right)^o \right]](https://tex.z-dn.net/?f=%5Cbf%2026%5Eo35%27%5Cimplies%2026%2B%5Cfrac%7B35%7D%7B60%7D%5Cimplies%20%5Ccfrac%7B1595%7D%7B60%7D%5Ciff%20%5Ccfrac%7B319%7D%7B12%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%2826%5Eo35%27%29%5Ciff%20tan%5Cleft%5B%20%5Cleft%28%20%5Ccfrac%7B391%7D%7B12%7D%20%5Cright%29%5Eo%20%5Cright%5D)
now, the angle is in degrees, thus, make sure your calculator is in Degree mode