Answer:
nElements = 0;
for (int i = 0; i < a2d.length; i++)
nElements += a2d[i].length;
isRectangular = true;
for (int i = 1; i < a2d.length && isRectangular; i++)
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Step-by-step explanation:
2 dimensional array is created and initialize element with 0. and the taking loop for 2 dimensional array .such as
n Elements = 0;
for (int i = 0; i < a2d.length; i++)
n Elements += a2d[i].length;
A boolean variable isRectangular and 2 dimensional array has been created if rectangle is true the take a2d.length and isRectangular less than i and intiliaze i with 1 then increment the i .It will give true value.
If rectangular is false then apply if statement and see if a2d[i] is not equal to a2d[0]
if (a2d[i].length != a2d[0].length)
isRectangular = false;
Answer:
x=4
Step-by-step explanation:
12=4-4x
4-4x=12
Add 4 to both sides
4x=16
Divide by 4
x=4
Answer:
I hope 3/4full is the correct answer
Answer:
it will depend on what the x value is, 18 would be greater if x is -5 or more, it will be equal if x equals -6.
The inner function g(x) has x-13 in the denominator. Set it equal to 0 and solve for x
x-13 = 0
x-13+13 = 0+13
x = 13
If x = 13 then the denominator of g(x) will be zero. This is a problem since you cannot divide by zero
So x = 13 is not allowed as an input in the g(x) function. The same applies for the composite function as well.
So that's why the domain is the set of all real numbers x but x cannot equal 13
This translates to what choice D is saying, so that is the answer
