Answer:
b
Inteligencia real Inteligencia
Explanation:
Answer:
Following are the program to this question:
#include <iostream> //defining header file
using namespace std;
int hailstoneLength(int n) //defining method hailstoneLength
{
int t=1; //defining integer variable assign
while(n!=1) //define a loop that checks value is not equal to 1
{
if(n%2==0) // check even number condition
{
n=n/2; // divide the value by 2 and store its remainder value in n
t++; //increment value of t by 1.
}
else
{
n=n*3+1; //calculate and hold value in n
t++; //increment value of t variable by 1
}
}
return t; //return value
}
int main() //defining main method
{
int n; //defining integer variable
cout<<"Enter any number: "; //print message
cin>> n; //input value
cout<<hailstoneLength(n); //call method and print its value
return 0;
}
Output:
Enter any number: 3
8
Explanation:
Program description can be given as follows:
- In the given C++ language program an integer method "hailstoneLength", is declared, that accepts an integer variable "n" in its parameter.
- Inside the method, an integer variable t is declared, that assign a value that is 1, in the next line, a while loop is declared, that uses if block to check even condition if number is even it divide by 2 and increment t variable value by 1.
- If the number is odd it will multiply the value by 3 and add 1 and increment t by 1 then it will go to if block to check value again. when value of n is not equal to 1 it will return t variable value.
- In the main method, an integer variable "n" is used that call the method and print its return value.
Computer is your best answer.
If you download the files, they will show up either on your computer home screen, or in the 'downloads' section of your computer files.
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