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2 years ago

13

I’ve done this over and over how do u do it?

1 answer:

myrzilka [38]2 years ago

3 0

Long division would take care of this nicely for you. In the box you will put this: $5 x^{4}+0 x^{3} +3 x^{2} +0x+8$ . Don't forget to leave a place for the x's that aren't there. Then do the division. The answer is A. I believe that it would be near impossible to show you how to do long division of polynomials in this particular forum.

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Solve for x in the following equation.

Marta_Voda [28]

An equation is formed of two equal expressions. The value of x in the given exponential equation is 10. The correct option is 10.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

In the given exponential equation $5^{x-2}=5^8$ , It can be observed that the base of both the sides of the equation is the same, therefore, 5. Therefore, the equation can be written as,

$5^{x-2}=5^8$

Since the base on both the sides are the same, comparing the exponential values on both sides,

x - 2 = 8

x = 8 + 2

x = 10

Hence, the value of x in the given exponential equation is 10.

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4 0

1 year ago

vredina [299]

No, the sequence is algebraic.

7 0

3 years ago

Write an expression that represents the product of q and 8, divided by 4.

Sholpan [36]

Answer:

8 q / 4 =2q

Step-by-step explanation

6 0

3 years ago

A soccer coach bought some new uniforms and cleats for his team.

natka813 [3]

Uhhhh i cant answer this without details

7 0

2 years ago

It takes machine A x hours to manufacture a deck of cards that machine B can manufacture in y hours. If machine A operates alone

nlexa [21]

Answer:

The expression that shows how long the two machines will operate simultaneously is:

$\frac{y(100x-z)}{x+y}$

Step-by-step explanation:

We know that:

x: hours to manufacture a deck of cards for machine A

y: hours to manufacture a deck of cards for machine B

z: hours that machine A operates alone

The number of decks manufactured only by machine A is:

$\frac{z}{x}$

So, the remaining decks are given by:

$100-\frac{z}{x}=\frac{100x-z}{x}$

Then, the combined rate of machines A and B would be:

$\frac{1}{x} +\frac{1}{y} =\frac{x+y}{xy}$

The work-rate formula is:

$Amount= Rate \times Time$

Hence, the time that the two machines work simultaneously is:

$Time=\frac{Amount}{Rate}$

$Time=\frac{Amount}{Rate} =\frac{\frac{100x-z}{x} }{\frac{x+y}{xy} } ={\frac{100x-z}{x} \times \frac{xy}{x+y}=\frac{y(100x-z)}{x+y}$

3 0

3 years ago