The value of “k” that will give two real roots is 25/48
Given the equation (1 – 3k) x^2 + 3x – 4, for the equation to have two real roots, this means that b^2 - 4ac > 0
From the given expression
a = 1 - 3k
b = 3
c = -4
Substitute into the equation b^2 - 4ac = 0
3^2 - 4(1 - 3k)(-4) = 0
9 + 16 (1-3k) = 0
9 + 16 - 48k =0
25 = 48k
k = 25/48
Hence the value of “k” that will give two real roots is 25/48
Learn more here: brainly.com/question/564715
Answer:
2.08%
Step-by-step explanation:
The probability of a snowfall on any given night is 1/8.
The probability that the father is telling the truth is 1 - 5/6, or 1/6.
Then:
1/6 x 1/8=1/48=0.0208, or 2.08% ............
Answer:
19
Step-by-step explanation:
-3q+5q=38
2q=38
q=19
please like my answer
<span>The results do not represent the population because the sample does not represent professors from different areas.</span>
Answer:
See below.
Step-by-step explanation:
I can do this but it's a pretty long proof. There might be a much easier way of proving this but this is the only way I can think of.
Write tan A as s/c and sec A as 1/c ( where s and c are sin A and cos A respectively).
Then tanA+ secA -1/ tanA - secA+1
= (s/c + 1/c - 1) / ( sc - 1/c + 1)
= (s + 1 - c) / c / (s - 1 + c) / c
= (s - c + 1) / (s + c - 1).
Now we write the right side of the identity ( 1 + sin A) / cos A as (1 + s) / c
So if the identity is true then:
(s - c + 1) / (s + c - 1) = (1 + s) / c.
Cross multiplying:
cs - c^2 + c = s + c - 1 + s^2 + cs - s
Simplifying:
cs - c^2 + c = cs - (1 - s^2) + c + s - s
Now the s will disappear on the right side and 1 - s^2 = c^2 so we have
cs - c^2 + c = cs - c^2 + c.
Which completes the proof.