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antiseptic1488 [7]
3 years ago
10

What’s the domain and zeroes of x-2/x^2+2x-35

Mathematics
1 answer:
Allushta [10]3 years ago
8 0

In the image, you can see, you have to factor the bottom function out first, and then solve for the zeros. let x = 0 and solve them. The domain is stated in the image as well.

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The height, in inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84. (
Schach [20]

Answer:

Step-by-step explanation:

Given that the height in  inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84.

X is N(64, 2.8)

Or Z = \frac{x-64}{2.8}

a)  the probability that the height of a randomly chosen woman is between 59.8 and 68.2 inches.

=P(59.8

b) P(X\geq 59)\\= P(X\geq -1.78)\\ \\=0.9625

c) For 4 women to be height 260 inches is equivalent to

4x will be normal with mean (64*4) and std dev (2.8*4)

4x is N(266, 11.2)

P(4x>260)= \\P(Z\geq -0.53571)\\=0.7054

d) Z is N(0,1)

E(Z19) = P(Z>19)\\= 0.000

since normal distribution is maximum only between 3 std deviations form the mean on either side.

3 0
3 years ago
A skateboarder starting from rest accelerates down a ramp at 2 m/s for 2 s. What is the final speed of the skateboarder
Sedaia [141]

Initial speed of the skateboard (u) = 0 m/s (Starts from rest)

Acceleration of the skateboard (a) = 2 m/s²

Time taken by the skateboard (t) = 2s

By using equation of motion, we get:

\bf \longrightarrow v = u + at \\  \\ \rm \longrightarrow v = 0 + 2 \times 2 \\  \\ \rm \longrightarrow v = 4 \: m {s}^{ - 1}

\therefore Final speed of the skateboard(v) = 4 m/s

7 0
3 years ago
please help. will give brainliest! review the table of values for function p(x). what is lim (x -14) p(x), if it exists? (table
Lubov Fominskaja [6]

Answer:

DNE

Step-by-step explanation:

The the given table, we have;

As x approaches -14 from the left, at x = -14.001,  p(x) = 1.96

\lim \limits _{x \to -14^{-}} p(x) = 1.96

As x approaches -14 from the right, at x = -13.999, p(x) = 1.97

\lim \limits _{x \to -14^{+}} p(x) = 1.97

The value of p(x) when x = -14 is \lim \limits _{x \to -14} p(x) = Undefined, or is not definable, therefore, p(x) Does Not Exist (DNE) when x = -14, and we have;

\lim \limits _{x \to -14} p(x)  Does Not Exist, DNE.

3 0
3 years ago
Graph the direct variation y=−1.5x. Using the graph, find:
Mariana [72]
Y=-3

-3=-1.5x
you substitiue y value, then you divide both sides by -1.5 and you get 2 for x.
(2,-3)

y=4.5
4.5=-1.5x
you substitute y value, then again you divide both sides by -1.5 and you get 3.
(3,4.5)



y=6
6=-1.5x
same thing for this last one. then once again divide by -1.5 and you get -4.
(-4,6)




7 0
3 years ago
PICK ALL THAT ARE EQUIVALENT TO -5/19
Vladimir [108]

Answer:

Step-by-step explanation:

The anwser is 2,3,4,5

6 0
3 years ago
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