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3 years ago

What’s the domain and zeroes of x-2/x^2+2x-35

Mathematics

1 answer:

Allushta [10]3 years ago

8 0

In the image, you can see, you have to factor the bottom function out first, and then solve for the zeros. let x = 0 and solve them. The domain is stated in the image as well.

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Y MORE THAN 4 is -36 translate for me please into math symbols then solve problem (list steps)

Sphinxa [80]

$y + 4 = -36

Subtract 4 both sides.

y = -40

Check solution. 

-40 + 4 = -36

This is correct.

You're welcome. 
$ Observe below please.

4 0

2 years ago

Ken had 5 math quizzes in a month.

Mnenie [13.5K]

Answer:

Choose the top right one.

Step-by-step explanation:

hoped i helped i really hope i helped. can you please please give me crown as well?

8 0

1 year ago

Read 2 more answers

Please help me with this

GREYUIT [131]

Ths phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be D. the sum of three times a number and six divided by the difference of seven times the number and nine.

<h3>How to illustrate the algebra?</h3>

It should be noted that an algebra is simply used to show the relationship between variables.

Here, the phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be the sum of three times a number and six divided by the difference of seven times the number and nine.

In conclusion, the correct option is D.

Learn more about algebra on:

brainly.com/question/723406

#SPJ1

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1 year ago

The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

lyudmila [28]

If $\mathcal C$ is the boundary of the triangle $D$ , then by Green's theorem

$\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23$

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2 years ago

Segment BC is a midsegment of triangle TUV. What is the length of segment VC? (A)a (B)2b (C)b (D)c

Ganezh [65]

It would be twice whatever the midsegment equals.

7 0

3 years ago